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Chemistry-

General

Easy

Question

Which of the following metal's oxide can be reducedbyFeasreducingagentattemperatureT₁?

Pb
Ca
Mg
None ofthese

The correct answer is: Pb

Related Questions to study

Whichofthegivenmetaloxidesis havingminimum thermaldecompositiontemperature?

Whichofthegivenmetaloxidesis havingminimum thermaldecompositiontemperature?

chemistry-General

Whichintheabovecurveiswronglypresented?

Whichintheabovecurveiswronglypresented?

chemistry-General

Allmineralsarenottheorebutall oresareminerals.The extraction of a particular metal depends uponseveral factorsandoverallithastobeconvenientand economical.
ThenBis:

Allmineralsarenottheorebutall oresareminerals.The extraction of a particular metal depends uponseveral factorsandoverallithastobeconvenientand economical.
ThenBis:

chemistry-General

parallel

Find out F:

Find out F:

chemistry-General

Find out E:

Find out E:

chemistry-General

Find out C:

Find out C:

chemistry-General

parallel

Find out B:

Find out B:

chemistry-General

Find out A:

Find out A:

chemistry-General

Which of the following particles is most unstable?

Which of the following particles is most unstable?

physics-General

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Extractionofaluminiumcanbeunderstoodby:

Electrolytic reduction of $A l subscript 2 end subscript O subscript 3 end subscript$
Electrolytic:( $A l subscript 2 end subscript O subscript 3 end subscript$ +Cryolite+ $C a F subscript 2 end subscript$ )
Cathode: Carbon inside the Fe-container
Anode: Graphite rods
The molten electrolytes contain $N a to the power of plus end exponent comma A l to the power of 3 plus end exponent$ , and $C a to the power of 2 plus end exponent$ only Al gets deposited at cathode because:

Extractionofaluminiumcanbeunderstoodby:

Electrolytic reduction of $A l subscript 2 end subscript O subscript 3 end subscript$
Electrolytic:( $A l subscript 2 end subscript O subscript 3 end subscript$ +Cryolite+ $C a F subscript 2 end subscript$ )
Cathode: Carbon inside the Fe-container
Anode: Graphite rods
The molten electrolytes contain $N a to the power of plus end exponent comma A l to the power of 3 plus end exponent$ , and $C a to the power of 2 plus end exponent$ only Al gets deposited at cathode because:

chemistry-General

Extraction of aluminium can be understood by:

Electrolytic reduction of $A l subscript 2 end subscript O subscript 3 end subscript$
Electrolytic:( $A l subscript 2 end subscript O subscript 3 end subscript$ +Cryolite+ $C a F subscript 2 end subscript$ )
Cathode: Carbon inside the Fe-container
Anode: Graphite rods
The function of fluorspar( $C a F subscript 2 end subscript$ )is:

Extraction of aluminium can be understood by:

Electrolytic reduction of $A l subscript 2 end subscript O subscript 3 end subscript$
Electrolytic:( $A l subscript 2 end subscript O subscript 3 end subscript$ +Cryolite+ $C a F subscript 2 end subscript$ )
Cathode: Carbon inside the Fe-container
Anode: Graphite rods
The function of fluorspar( $C a F subscript 2 end subscript$ )is:

chemistry-General

In the following nuclear reaction $blank subscript 13 end subscript A l to the power of 27 end exponent plus blank subscript 2 end subscript H e to the power of 4 end exponent rightwards arrow blank subscript 15 end subscript P to the power of 30 end exponent plus X$ , X will be

In the following nuclear reaction $blank subscript 13 end subscript A l to the power of 27 end exponent plus blank subscript 2 end subscript H e to the power of 4 end exponent rightwards arrow blank subscript 15 end subscript P to the power of 30 end exponent plus X$ , X will be

physics-General

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When $blank subscript 15 end subscript P to the power of 30 end exponent$ decays to become $blank subscript 14 end subscript S i to the power of 30 end exponent$ , the particle released is

When $blank subscript 15 end subscript P to the power of 30 end exponent$ decays to become $blank subscript 14 end subscript S i to the power of 30 end exponent$ , the particle released is

physics-General

The binding energies of a deutron and an $alpha$ -particle are 1.125, 7.2 MeV/nucleon respectively. The more stable of the two, is

The binding energies of a deutron and an $alpha$ -particle are 1.125, 7.2 MeV/nucleon respectively. The more stable of the two, is

physics-General

Observe the following statements regarding isotones
i) $blank to the power of 39 end exponent K subscript 19 end subscript$ and $blank to the power of 40 end exponent C a subscript 20 end subscript$ are isotones
ii) Nuclides having different atomic numbers (z) and mass number (A) but same number of neutrons (n) are called Isotones
iii) $blank to the power of 19 end exponent F subscript 9 end subscript text and end text blank to the power of 23 end exponent N a subscript 11 end subscript$ are isotone

Observe the following statements regarding isotones
i) $blank to the power of 39 end exponent K subscript 19 end subscript$ and $blank to the power of 40 end exponent C a subscript 20 end subscript$ are isotones
ii) Nuclides having different atomic numbers (z) and mass number (A) but same number of neutrons (n) are called Isotones
iii) $blank to the power of 19 end exponent F subscript 9 end subscript text and end text blank to the power of 23 end exponent N a subscript 11 end subscript$ are isotone

physics-General

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