Maths-
General
Easy

Question

Determine whether a linear , quadratic or exponential function best models the data . Then use regression to find the function that models the data ?

hintHint:

1. When the difference between 2 consecutive output values (y values) for a given constant change in the input values (x values) is constant. i.e. y(n)- y(n-1) is constant for any value of n, the function is known as a linear function.
2. Regression is a statistical tool used to find a model that can represent the relation between a given change in dependant variable (output values/ y values) for a given change in independent variable (input values/ x values).
Linear Equation using regression can be represented as-
Y = a + bX, where-
a =fraction numerator left square bracket left parenthesis Σy right parenthesis left parenthesis Σx squared right parenthesis space minus space left parenthesis Σx right parenthesis space left parenthesis Σxy right parenthesis right square bracket over denominator left square bracket straight n left parenthesis Σx squared right parenthesis space minus space left parenthesis Σx right parenthesis squared right square bracket end fraction
b=fraction numerator space left square bracket straight n left parenthesis Σxy right parenthesis space minus space left parenthesis Σx right parenthesis space left parenthesis Σy right parenthesis right square bracket over denominator left square bracket straight n left parenthesis Σx squared right parenthesis space minus space left parenthesis Σx right parenthesis squared right square bracket end fraction

The correct answer is: The given function is a linear function and using Regression, the given function can be modelled into the equation- Y = 100.02 - 10.55X.


    Step-by-step solution:-
    From the given table, we observe the following readings-

    x1 = 0, y1 = 100;
    x2 = 1, y2 = 89.5;
    x3 = 2, y3 = 78.9;
    x4 = 3, y4 = 68.4;
    x5 = 4, y5 = 57.8
    a). Difference between 2 consecutive x values-
                                                                                             dx1 = x2 - x1 = 1 - 0 = 1
                                                                                             dx2 = x3 - x2 = 2 - 1 = 1
                                                                                             dx3 = x4 - x3 = 3 - 2 = 1
                                                                                             dx4 = x5 - x4 = 4 - 3 = 1
    Difference between 2 consecutive y values-
                                                                                    dy1 = y2 - y1 = 89.5 - 100 = -10.5
                                                                                    dy2 = y3 - y2 = 78.9 - 89.5 = -10.6
                                                                                    dy3 = y4 - y3 = 68.4 - 78.9 = -10.5
                                                                                    dy4 = y5 - y4 = 57.8 - 68.4 = -10.6
    We observe that the difference for every consecutive x values is constant i.e. 1 and for y values the difference is almost constant i.e. -10.5.
    Hence, the given function is a linear function.
    Using Linear Regression formula-
    Y = a + bX, where-
                                                                                      a =fraction numerator left square bracket left parenthesis Σy right parenthesis left parenthesis Σx squared right parenthesis space minus space left parenthesis Σx right parenthesis space left parenthesis Σxy right parenthesis right square bracket over denominator space left square bracket straight n left parenthesis Σx squared right parenthesis space minus space left parenthesis Σx right parenthesis squared right square bracket end fraction
                                                                               ∴ a =  [fraction numerator left square bracket left parenthesis 394.6 right parenthesis left parenthesis 30 right parenthesis space minus space left parenthesis 10 right parenthesis left parenthesis 683.7 right parenthesis right square bracket over denominator left square bracket 5 left parenthesis 30 right parenthesis space minus space left parenthesis 10 right parenthesis squared right square bracket end fraction.......................... (As per adjacent table)
    ∴ a = fraction numerator left parenthesis 11 comma 838 space minus space 6 comma 837 right parenthesis over denominator left parenthesis 150 space minus space 100 right parenthesis end fraction 
                                                                                                 ∴ a = fraction numerator 5 comma 001 over denominator 50 end fraction
                                                                                                 ∴ a = 100.02
                                                                                        b = fraction numerator left square bracket straight n left parenthesis Σxy right parenthesis space minus space left parenthesis Σx right parenthesis space left parenthesis Σy right parenthesis right square bracket over denominator left square bracket straight n left parenthesis Σx squared right parenthesis space minus space left parenthesis Σx right parenthesis squared right square bracket end fraction
                                                                                 ∴ b =  fraction numerator space left square bracket 5 left parenthesis 683.7 right parenthesis space minus space left parenthesis 10 right parenthesis left parenthesis 394.6 right parenthesis right square bracket over denominator left square bracket 5 left parenthesis 30 right parenthesis space minus space left parenthesis 10 right parenthesis squared right square bracket end fraction
                                                                                     ∴ b = fraction numerator left parenthesis 3 comma 418.5 space minus space 3 comma 946 right parenthesis over denominator left parenthesis 150 space minus space 100 right parenthesis end fraction
                                                                                               ∴ b =fraction numerator negative 527.5 over denominator 50 end fraction 
                                                                                                ∴ b = -10.55
    ∴ The Linear Equation is-
                                                                                                    Y = a + bX
                                                                                        ∴ Y = 100.02 + (-10.55)X
                                                                                          ∴ Y = 100.02 - 10.55X
    Final Answer:-
    ∴ The given function is a linear function and using Regression, the given function can be modelled into the equation- Y = 100.02 - 10.55X.

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