Find a counterexample to show that the following conjecture is false.
Conjecture: The square of any integer is always greater than the integer.

The correct answer is: given statement is false.

We have given, the square of every integer is always greater than the integer.
We have to prove that given statement false.
Number obtained when a number is multiplied by itself three times is called a cube number.
If m = n², then m is a perfect square  where m and n are natural numbers.
Example: consider 1
Square of 1 = 1
Example: consider 2
Square of 2 = 4
Therefore, the square of every natural number is not always greater than the number itself.
Therefore, given statement is false.