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Maths-

General

Easy

Question

Find the equation for a path that passes through the point (6, 6) and is perpendicular to $y equals negative 3 over 4 x plus 1$ .

hint Hint:

Perpendicular lines are lines that intersect at a right angle.

The correct answer is: y = 4/3x - 2

We have been given an equation that represents y-axis.

We have to find an equation for a path that passes through the point (6, 6) and is perpendicular to $y equals fraction numerator negative 3 over denominator 4 end fraction x plus 1$

Step 1 of 1:
We have given a line passes through a point (6, 6) and perpendicular to a line $y equals fraction numerator negative 3 over denominator 4 end fraction x plus 1$
Since product of two perpendicular lines is equal to -1.
So,
$m cross times fraction numerator negative 3 over denominator 4 end fraction equals negative 1$
$m equals 4 over 3$
Therefore the equation of the line will be
$y minus 6 equals 4 over 3 left parenthesis x minus 6 right parenthesis$
$y equals 4 over 3 x minus 2$

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