Maths-
General
Easy

Question

Find the Quotient and the domain .
fraction numerator y squared minus 16 over denominator y squared minus 10 y plus 25 end fraction divided by fraction numerator 3 y minus 12 over denominator y squared minus 3 y minus 10 end fraction

hintHint:

The expansions of certain identities are:
table attributes columnalign right columnspacing 0em end attributes row cell left parenthesis straight x plus straight a right parenthesis left parenthesis straight x plus straight b right parenthesis equals straight x squared plus left parenthesis straight a plus straight b right parenthesis straight x plus ab end cell row cell open parentheses straight x squared minus straight a squared close parentheses equals left parenthesis straight x minus straight a right parenthesis left parenthesis straight x plus straight a right parenthesis space space space space space space space space space space space space space space end cell end table
Finding the quotient is same as division. Dividing a number and multiplying it with a reciprocal of the number have the same effect.
We are asked to find the quotient and the domain of the expression.

The correct answer is: Thus, the domain is, (-∞,5)∪(5,∞)


    Step 1 of 3:
    The given expression is fraction numerator straight y squared minus 16 over denominator straight y squared minus 10 straight y plus 25 end fraction divided by fraction numerator 3 straight y minus 12 over denominator straight y squared minus 3 straight y minus 10 end fraction.
    Take the reciprocal of the second expression and then multiply it with the first one. This has the same effect as the given expression.
    Thus, we have:
    fraction numerator straight y squared minus 16 over denominator straight y squared minus 10 straight y plus 25 end fraction cross times fraction numerator straight y squared minus 3 straight y minus 10 over denominator 3 straight y minus 12 end fraction
    Step 2 of 3:
    Simplify the expression and cancel out the common factors;
    fraction numerator straight y squared minus 16 over denominator straight y squared minus 10 straight y plus 25 end fraction cross times fraction numerator straight y squared minus 3 straight y minus 10 over denominator 3 straight y minus 12 end fraction equals fraction numerator straight y squared minus 4 squared over denominator straight y squared minus 5 straight y minus 5 straight y plus 25 end fraction cross times fraction numerator straight y squared minus 5 straight y plus 2 straight y minus 10 over denominator 3 left parenthesis straight y minus 4 right parenthesis end fraction
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell equals fraction numerator left parenthesis y minus 4 right parenthesis left parenthesis y plus 4 right parenthesis over denominator y left parenthesis y minus 5 right parenthesis minus 5 left parenthesis y minus 5 right parenthesis end fraction cross times fraction numerator y left parenthesis y minus 5 right parenthesis plus 2 left parenthesis y minus 5 right parenthesis over denominator 3 left parenthesis y minus 4 right parenthesis end fraction end cell row cell equals fraction numerator left parenthesis y minus 4 right parenthesis left parenthesis y plus 4 right parenthesis over denominator left parenthesis y minus 5 right parenthesis left parenthesis y minus 5 right parenthesis end fraction cross times fraction numerator left parenthesis y plus 2 right parenthesis left parenthesis y minus 5 right parenthesis over denominator 3 left parenthesis y minus 4 right parenthesis end fraction space space space space space space space space space space space space space space space space space end cell end table
    equals fraction numerator left parenthesis straight y plus 4 right parenthesis left parenthesis straight y plus 2 right parenthesis over denominator 3 left parenthesis straight y minus 5 right parenthesis end fraction
    Thus, the quotient is, equals fraction numerator left parenthesis straight y plus 4 right parenthesis left parenthesis straight y plus 2 right parenthesis over denominator 3 left parenthesis straight y minus 5 right parenthesis end fraction
    Step 3 of 3:
    The domain of a rational expression should exclude the values for which the denominator attains a zero values. So, when
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 3 left parenthesis y minus 5 right parenthesis equals 0 end cell row cell y minus 5 equals 0 space space space space space end cell row cell y equals 5 space space space space space space space space space space space end cell end table
    Thus, the domain is, (-∞,5)∪(5,∞)

    We have to state the domain of a rational expression while simplifying them because we must exclude zeros of a denominator as dividing with zero is not defined.

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    A Basketball coach is considering three players for most valuable player . The table shows the proportion of shots each player made of the shots they attempted.


    a) For a technical foul , the team can pick any player they want to shoot the free throw. Which player should the team pick ?
    b) Which player is most successful with their field goal shots? Explain.
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    In this question, it can be explained further:
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    A Basketball coach is considering three players for most valuable player . The table shows the proportion of shots each player made of the shots they attempted.


    a) For a technical foul , the team can pick any player they want to shoot the free throw. Which player should the team pick ?
    b) Which player is most successful with their field goal shots? Explain.
    c) Rank the players by the percentage of the 3- point shots each made .
    d) If all the players attempted the same number of shots , which player would you choose as the most valuable player? Justify your answer.

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    In this question, it can be explained further:
    A. Kimberly: 0.857 > 4/5 > 71%
    Here, Kimberly's free throws have the highest proportion.
    B. Martin: 49.5% > 9/20 > 0.448
    Here, Martin's proportion of field goals is the highest.
    C. Corey: 0.338 > 1/3 > 32%
    Kimberly > Corey > Martin
    From the above explanation, we can conclude Kimberly is first, Corey is second, and Martin is third.
    I'd go with Kimberly because he has a higher percentage on all shots than the other two players.

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