Maths-
General
Easy

Question

Find the solution of the system of equations.
y equals negative 2 x squared plus 6 x minus 7
y = 13 - 2x

hintHint:

Hint:
The quadratic formula corresponding to the equation ax2 +bx + c = 0 is fraction numerator negative b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction.
We are asked to solve the given set of equation..

The correct answer is: We are asked to solve the given set of equation.


    Step 1 of 2:
    The LHS of the set of equation has the same value. Thus, equate the RHS of the equations.
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 13 minus 2 x equals negative 2 x squared plus 6 x minus 7 space space end cell row cell 2 x squared minus 6 x minus 2 x plus 13 plus 7 equals 0 end cell row cell 2 x squared minus 8 x plus 20 equals 0 space space space space space space space space space space space space space space end cell row cell x squared minus 4 x plus 10 equals 0 space space space space space space space space space space space space space space space space space end cell end table
    We factorize the two out of the equation to get the simplified form.
    Step 2 of 2:
    Solve the simplified equation using the quadratic formula.
    here; a equals 1 comma b equals negative 4 straight & c equals 10
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell fraction numerator negative b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction equals fraction numerator negative left parenthesis negative 4 right parenthesis plus-or-minus square root of left parenthesis negative 4 right parenthesis squared minus 4 left parenthesis 1 right parenthesis left parenthesis 10 right parenthesis end root over denominator 2 left parenthesis 1 right parenthesis end fraction end cell row cell equals fraction numerator 4 plus-or-minus square root of 16 minus 40 end root space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space over denominator 2 end fraction end cell row cell equals fraction numerator 4 plus-or-minus square root of negative 36 end root over denominator 2 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space end cell end table
    Here, a negative value comes in the root. So, there exists no real root corresponding to the equation.

    It is not necessary that every single quadratic equation would have two sets of real solution.

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