Find the vertex, axis of symmetry and sketch the graph of the function f(x)= x²+50

The correct answer is: Hence, the vertex of the parabola is (0,50) and the axis of the symmetry is x = 0

Hint:
The vertex form of a quadratic function is
f(x) = a(x – h)² + k
Where a, h, and k are constants. Here, h represents horizontal translation, a represents vertical translation and (h,k) is the vertex of the parabola. Also, a represents the Vertical stretch/shrink of the parabola and if a is negative, then the graph is reflected over the x-axis.
The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.
Solution
Given, f(x)= x²+50
Here, h = 0, k = 50
So, the vertex of the parabola is (0,50) and the axis of the symmetry is x = 0
The graph can be plotted as

Final Answer:
Hence, the vertex of the parabola is (0,50) and the axis of the symmetry is x = 0.