Question
How much should 3x2 -5xy +7y2 +3 be increased to get 5x2-7xy-3y4+3x
Hint:
Addition of polynomials.
○ Always take like terms together while performing addition.
○ In addition to polynomials only terms with the same coefficient are added.
The correct answer is: Hence, the other term must add is - 3y4 - 7y2 + 2x2 - 2xy + 3x - 3.
Answer:
- Step by step explanation:
○ Given:
Terms:
3x2 -5xy +7y2 +3
5x2-7xy-3y4+3x
○ Step 1:
○ Let A must be added to 3x2 -5xy +7y2 +3 to get 5x2-7xy-3y4+3x.
So,
A +3x2 -5xy +7y2 +3 = 5x2-7xy-3y4+3x
A = (5x2-7xy-3y4+3x ) - ( 3x2 -5xy +7y2 +3 )
A = - 3y4 - 7y2 + 5x2 - 3x2- 7xy + 5xy + 3x - 3
A = - 3y4 - 7y2 + 2x2 - 2xy + 3x - 3
A = - 3y4 - 7y2 + 2x2 - 2xy + 3x - 3
- Final Answer:
Hence, the other term must add is - 3y4 - 7y2 + 2x2 - 2xy + 3x - 3.
○ Step 1:
○ Let A must be added to 3x2 -5xy +7y2 +3 to get 5x2-7xy-3y4+3x.
So,
A +3x2 -5xy +7y2 +3 = 5x2-7xy-3y4+3x A = (5x2-7xy-3y4+3x ) - ( 3x2 -5xy +7y2 +3 ) A = - 3y4 - 7y2 + 5x2 - 3x2- 7xy + 5xy + 3x - 3 A = - 3y4 - 7y2 + 2x2 - 2xy + 3x - 3 A = - 3y4 - 7y2 + 2x2 - 2xy + 3x - 3Related Questions to study
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¶The standard form of a linear equation in one variable is: ax + b = 0
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