Maths-
General
Easy
Question
Ms. Simon drives her car from her home to her workplace every workday morning. The table above shows the distance, in miles, and her average driving speed, in miles per hour (mph), when there is no traffic delay, for each segment of her drive.
If Ms. Simon starts her drive at 6:30 a.m., she can drive at her average driving speed with no traffic delay for each segment of the drive. If she starts her drive at 7:00 a.m., the travel time from the freeway entrance to the freeway exit increases by 33% due to slower traffic, but the travel time for each of the other two segments of her drive does not change. Based on the table, how many more minutes does Ms. Simon take to arrive at her workplace if she starts her drive at 7:00 a.m. than if she starts her drive at 6:30 a.m.? (Round your answer to the nearest minute.)
The correct answer is: 6
We are given that,
Ms. Simon travels 15.4 miles on the freeway,
Average speed for portion of the trip when there is no traffic delay.
Average speed = 50 miles per hour
Therefore, when there is no traffic delay, the time Ms. Simon spends on the freeway is
Distance/ speed = time
15.4 miles / 50 mph = 0.308 hours
Since there are 60 minutes in one hour, time in minutes she spends on the freeway when there
is no delay
(0.308) (60) = 18.48 minutes
Leaving at 7:00 a.m. results in a trip that is 33% longer,
So we have to find 33% of time
33% of 18.48 minutes = ()18.48
= 6.16
The travel time for each of the other two segments does not change.
We will round of the value to the nearest minute i.e. 6 minutes
Therefore, it takes Ms. Simon 6 more minutes to drive to her workplace when she leaves at 7:00 a. m
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