Maths-
General
Easy

Question

In 2015 the populations of City X and City Y were equal. From 2010 to 2015 , the population of City X increased by 20% and the population of City  decreased by 10%. If the population of City  was 120,000 in 2010 , what was the population of City Y in 2010?

  1. 60000
  2. 90000
  3. 160000
  4. 240000

hintHint:

Hint:
  • A percentage is a number or ratio that can be expressed as a fraction of 100.

The correct answer is: 160000


    Explanation:
    • We have given In 2015 the populations of City X and City Y were equal. From 2010 to 2015, the population of City X increased by 20% and the population of City Y decreased by 10%
    • We have to find what was the population of City Y in 2010.
    Step 1 of 1:
    1: population of city x in 2010 = 120000
    it increases by 20 % in 5 years . so in 2015 it will be
    ∣ 20 divided by 100 cross times 120000 equals 24000 equals 120000 plus 24000 equals 144000
    Thus population of city x in 2015 is 144000.
    2: the population of city x and y are same in year 2015.
    3: to find= population of city y in 2010 .if it reduces by 10% in 5 years.it will be 10 % more in year 2010
    4: let population of city y in year 2015 be 100.
    it gets increased by 10% =90
    thus-
    100 divided by 90 equals 144000 divided by x
    x equals 144000 cross times 100 over 90
    X =160000
    population of city x is .
    Hence, Option C is correct.

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