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Maths-

General

Easy

Question

In $straight triangle A B C comma s squared tan space A over 2 tan space B over 2 tan space C over 2 equals$

Δ
2Δ
R
4R

The correct answer is: Δ

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In $straight triangle A B C comma 4 R sin space A over 2 sin space B over 2 sin space straight C over 2 equals$

In $straight triangle A B C comma 4 R sin space A over 2 sin space B over 2 sin space straight C over 2 equals$

One quarter sector is cat from a uniform circular disc of radius R. This sector has mass M. It is made to rotate about a line perpendicular to its plane and passing through the center of the original disc. Its moment of inertia about the axis of rotation is...

One quarter sector is cat from a uniform circular disc of radius R. This sector has mass M. It is made to rotate about a line perpendicular to its plane and passing through the center of the original disc. Its moment of inertia about the axis of rotation is...

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In ΔABC , 4Rcos $A over 2$ cos $B over 2$ cos $C over 2$ =

In ΔABC , 4Rcos $A over 2$ cos $B over 2$ cos $C over 2$ =

parallel

In $straight triangle A B C comma sum a cos space A equals$

In $straight triangle A B C comma sum a cos space A equals$

A circular disc of radius R and thickness R/6 has moment of inertia about an axis passing through its center and perpendicular to its plane. It is melted and re casted in to a solid sphere. The moment of inertia of the sphere about its diameter as axis of rotation is.

A circular disc of radius R and thickness R/6 has moment of inertia about an axis passing through its center and perpendicular to its plane. It is melted and re casted in to a solid sphere. The moment of inertia of the sphere about its diameter as axis of rotation is.

physics-General

A ring of mass M and radius r is melted and then molded in to a sphere then the moment of inertia of the sphere will be.....

A ring of mass M and radius r is melted and then molded in to a sphere then the moment of inertia of the sphere will be.....

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parallel

In $straight triangle A B C comma sum fraction numerator open parentheses b squared minus c squared close parentheses over denominator a end fraction cos space A equals$

In $straight triangle A B C comma sum fraction numerator open parentheses b squared minus c squared close parentheses over denominator a end fraction cos space A equals$

One solid sphere A and another hollow sphere B are of the same mass and same outer radii. The moment of inertia about their diameters are respectively I_A and I_B such that....

One solid sphere A and another hollow sphere B are of the same mass and same outer radii. The moment of inertia about their diameters are respectively I_A and I_B such that....

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$Lt subscript x not stretchy rightwards arrow pi over 6 end subscript space open parentheses fraction numerator 3 sin space x minus square root of 3 cos space x over denominator 6 x minus pi end fraction close parentheses equals$

$Lt subscript x not stretchy rightwards arrow pi over 6 end subscript space open parentheses fraction numerator 3 sin space x minus square root of 3 cos space x over denominator 6 x minus pi end fraction close parentheses equals$

parallel

If $L subscript x not stretchy rightwards arrow 0 end subscript open parentheses fraction numerator cos begin display style space end style 4 x plus a cos space 2 x plus b over denominator x to the power of 4 end fraction close parentheses$

If $L subscript x not stretchy rightwards arrow 0 end subscript open parentheses fraction numerator cos begin display style space end style 4 x plus a cos space 2 x plus b over denominator x to the power of 4 end fraction close parentheses$

One circular rig and one circular disc both are having the same mass and radius. The ratio of their moment of inertia about the axes passing through their centers and perpendicular to their planes, will be,.....

One circular rig and one circular disc both are having the same mass and radius. The ratio of their moment of inertia about the axes passing through their centers and perpendicular to their planes, will be,.....

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A circular plate of uniform thickness has a diameter of 56 . A circular portion of diameter 42 cm . is removed from +ve x edge of the plate. Find the position of center of mass of the remaining portion with respect to center of mass of whole plate

A circular plate of uniform thickness has a diameter of 56 . A circular portion of diameter 42 cm . is removed from +ve x edge of the plate. Find the position of center of mass of the remaining portion with respect to center of mass of whole plate

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If f(x) = $x tan to the power of negative 1 end exponent$ x then $lim for x not stretchy rightwards arrow 1 of fraction numerator f left parenthesis x right parenthesis minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction equals$

If f(x) = $x tan to the power of negative 1 end exponent$ x then $lim for x not stretchy rightwards arrow 1 of fraction numerator f left parenthesis x right parenthesis minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction equals$

From a uniform circular disc of radius R, a circular disc of radius R/6 and having center at a distance +R/2 from the ceater of the disc is removed. Determine the center of mass of remaining portion of the disc.

From a uniform circular disc of radius R, a circular disc of radius R/6 and having center at a distance +R/2 from the ceater of the disc is removed. Determine the center of mass of remaining portion of the disc.

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$L subscript n not stretchy rightwards arrow straight infinity end subscript L t open square brackets 1 over n squared sec squared space 1 over n squared plus 2 over n squared sec squared space 4 over n squared plus midline horizontal ellipsis times plus 1 over n sec squared space 1 close square brackets equals$

$L subscript n not stretchy rightwards arrow straight infinity end subscript L t open square brackets 1 over n squared sec squared space 1 over n squared plus 2 over n squared sec squared space 4 over n squared plus midline horizontal ellipsis times plus 1 over n sec squared space 1 close square brackets equals$

parallel

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