Maths-
General
Easy

Question

Lt subscript x not stretchy rightwards arrow pi over 6 end subscript space open parentheses fraction numerator 3 sin space x minus square root of 3 cos space x over denominator 6 x minus pi end fraction close parentheses equals

  1. square root of 3
  2. fraction numerator 1 over denominator square root of 3 end fraction
  3. negative square root of 3
  4. fraction numerator negative 1 over denominator square root of 3 end fraction

The correct answer is: fraction numerator 1 over denominator square root of 3 end fraction

Related Questions to study

General
maths-

If L subscript x not stretchy rightwards arrow 0 end subscript open parentheses fraction numerator cos begin display style space end style 4 x plus a cos space 2 x plus b over denominator x to the power of 4 end fraction close parentheses

If L subscript x not stretchy rightwards arrow 0 end subscript open parentheses fraction numerator cos begin display style space end style 4 x plus a cos space 2 x plus b over denominator x to the power of 4 end fraction close parentheses

maths-General
General
physics-

One circular rig and one circular disc both are having the same mass and radius. The ratio of their moment of inertia about the axes passing through their centers and perpendicular to their planes, will be,.....

One circular rig and one circular disc both are having the same mass and radius. The ratio of their moment of inertia about the axes passing through their centers and perpendicular to their planes, will be,.....

physics-General
General
physics-

A circular plate of uniform thickness has a diameter of 56 . A circular portion of diameter 42 cm . is removed from +ve  x edge of the plate. Find the position of center of mass of the remaining portion with respect to center of mass of whole plate

A circular plate of uniform thickness has a diameter of 56 . A circular portion of diameter 42 cm . is removed from +ve  x edge of the plate. Find the position of center of mass of the remaining portion with respect to center of mass of whole plate

physics-General
parallel
General
maths-

If f(x) = x tan to the power of negative 1 end exponent x then lim for x not stretchy rightwards arrow 1 of   fraction numerator f left parenthesis x right parenthesis minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction equals

If f(x) = x tan to the power of negative 1 end exponent x then lim for x not stretchy rightwards arrow 1 of   fraction numerator f left parenthesis x right parenthesis minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction equals

maths-General
General
physics-

From a uniform circular disc of radius R, a circular disc of radius R/6 and having center at a distance +R/2 from the ceater of the disc is removed. Determine the center of mass of remaining portion of the disc.

From a uniform circular disc of radius R, a circular disc of radius R/6 and having center at a distance +R/2 from the ceater of the disc is removed. Determine the center of mass of remaining portion of the disc.

physics-General
General
maths-

L subscript n not stretchy rightwards arrow straight infinity end subscript L t open square brackets 1 over n squared sec squared space 1 over n squared plus 2 over n squared sec squared space 4 over n squared plus midline horizontal ellipsis times plus 1 over n sec squared space 1 close square brackets equals

L subscript n not stretchy rightwards arrow straight infinity end subscript L t open square brackets 1 over n squared sec squared space 1 over n squared plus 2 over n squared sec squared space 4 over n squared plus midline horizontal ellipsis times plus 1 over n sec squared space 1 close square brackets equals

maths-General
parallel
General
physics-

Four particles A,B,C and D of masses m,2 m,3 m and 5 m respectively are placed at corners of a square of side x as shown in figure find the coordinate of center of mass take A. at origin of x-y plane

Four particles A,B,C and D of masses m,2 m,3 m and 5 m respectively are placed at corners of a square of side x as shown in figure find the coordinate of center of mass take A. at origin of x-y plane

physics-General
General
maths-

stack L t with n not stretchy rightwards arrow straight infinity below fraction numerator 1 plus 2 to the power of 4 plus 3 to the power of 4 plus midline horizontal ellipsis plus n to the power of 4 over denominator n to the power of 5 end fraction minus L t fraction numerator 1 plus 2 cubed plus 3 cubed plus.. plus n cubed over denominator n to the power of 4 end fraction equals

stack L t with n not stretchy rightwards arrow straight infinity below fraction numerator 1 plus 2 to the power of 4 plus 3 to the power of 4 plus midline horizontal ellipsis plus n to the power of 4 over denominator n to the power of 5 end fraction minus L t fraction numerator 1 plus 2 cubed plus 3 cubed plus.. plus n cubed over denominator n to the power of 4 end fraction equals

maths-General
General
maths-

If f left parenthesis x plus y right parenthesis equals f left parenthesis x right parenthesis f left parenthesis y right parenthesis plus x comma y and f left parenthesis 5 right parenthesis equals 2 comma f to the power of straight prime left parenthesis 0 right parenthesis equals 3

If f left parenthesis x plus y right parenthesis equals f left parenthesis x right parenthesis f left parenthesis y right parenthesis plus x comma y and f left parenthesis 5 right parenthesis equals 2 comma f to the power of straight prime left parenthesis 0 right parenthesis equals 3

maths-General
parallel
General
physics-

Consider a two-particle system with the particles having masses M1, and m2. If the first particle is pushed towards the center of mass through a distance d, by what distance should the second particle be moved so as to keep the center of mass at the same position?

Consider a two-particle system with the particles having masses M1, and m2. If the first particle is pushed towards the center of mass through a distance d, by what distance should the second particle be moved so as to keep the center of mass at the same position?

physics-General
General
Maths-

For x element of R Lt subscript x not stretchy rightwards arrow straight infinity end subscript space open parentheses fraction numerator x minus 3 over denominator x plus 2 end fraction close parentheses to the power of x equals

There are seven indeterminate forms which are typically considered in the literature
{\displaystyle {\frac {0}{0}},~{\frac {\infty }{\infty }},~0\times \infty ,~\infty -\infty ,~0^{0},~1^{\infty },{\text{ and }}\infty ^{0}.}:

For x element of R Lt subscript x not stretchy rightwards arrow straight infinity end subscript space open parentheses fraction numerator x minus 3 over denominator x plus 2 end fraction close parentheses to the power of x equals

Maths-General

There are seven indeterminate forms which are typically considered in the literature
{\displaystyle {\frac {0}{0}},~{\frac {\infty }{\infty }},~0\times \infty ,~\infty -\infty ,~0^{0},~1^{\infty },{\text{ and }}\infty ^{0}.}:

General
physics-

Three particles of the same mass lie in the (X,Y) plane, The (X,Y) coordinates of their positions are (1,1),(2,2) and (3,3) respectively. The (X,Y) coordinates of the center of mass are

Three particles of the same mass lie in the (X,Y) plane, The (X,Y) coordinates of their positions are (1,1),(2,2) and (3,3) respectively. The (X,Y) coordinates of the center of mass are

physics-General
parallel
General
Maths-

Lt subscript h not stretchy rightwards arrow 0 end subscript space fraction numerator f open parentheses 2 h plus 2 plus h squared close parentheses minus f left parenthesis 2 right parenthesis over denominator f open parentheses h minus h squared plus 1 close parentheses minus f left parenthesis 1 right parenthesis end fraction given that f to the power of † left parenthesis 2 right parenthesis equals 6 text  and  end text f to the power of † left parenthesis 1 right parenthesis equals 4

We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 or fraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

Lt subscript h not stretchy rightwards arrow 0 end subscript space fraction numerator f open parentheses 2 h plus 2 plus h squared close parentheses minus f left parenthesis 2 right parenthesis over denominator f open parentheses h minus h squared plus 1 close parentheses minus f left parenthesis 1 right parenthesis end fraction given that f to the power of † left parenthesis 2 right parenthesis equals 6 text  and  end text f to the power of † left parenthesis 1 right parenthesis equals 4

Maths-General

We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 or fraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

General
Maths-

Lim subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator x tan space 2 x minus 2 x tan space x over denominator left parenthesis 1 minus cos space 2 x right parenthesis squared end fraction equals

We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 or fraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

Lim subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator x tan space 2 x minus 2 x tan space x over denominator left parenthesis 1 minus cos space 2 x right parenthesis squared end fraction equals

Maths-General

We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 or fraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

General
Maths-

If f left parenthesis a right parenthesis equals 2 comma f to the power of straight prime left parenthesis a right parenthesis equals 1 comma g left parenthesis a right parenthesis equals negative 1 comma g to the power of factorial left parenthesis a right parenthesis equals 2, then the value of Lim subscript x not stretchy rightwards arrow a end subscript space fraction numerator g left parenthesis x right parenthesis f left parenthesis a right parenthesis minus g left parenthesis a right parenthesis f left parenthesis x right parenthesis over denominator x minus a end fraction is

We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 orfraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

If f left parenthesis a right parenthesis equals 2 comma f to the power of straight prime left parenthesis a right parenthesis equals 1 comma g left parenthesis a right parenthesis equals negative 1 comma g to the power of factorial left parenthesis a right parenthesis equals 2, then the value of Lim subscript x not stretchy rightwards arrow a end subscript space fraction numerator g left parenthesis x right parenthesis f left parenthesis a right parenthesis minus g left parenthesis a right parenthesis f left parenthesis x right parenthesis over denominator x minus a end fraction is

Maths-General

We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 orfraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.