Maths-
General
Easy

Question

In the adjacent figure, points  B, A, D are collinear and  AD = AC.
Given that straight angle space BAC equals 50 to the power of ring operatorand straight angle B C D equals 80 to the power of ring operator. Find  straight angle space ABC space text  and   end text straight angle space ACB.

hintHint:

Find ∠ ACD from ∠BAC and condition AD = AC .Now , find  ∠ ACB from
∠BCD and ∠ ACD  .Now, Find  ∠DBC  using sum of angles in triangle ABC.

The correct answer is: ∠ ABC = 75°


    Step 1:-Find ∠ ACD
    Angles opposite to equal sides in a triangle are equal
    As AD =AC then ∠ADC = ∠ACD
    We  know that in a triangle, the exterior angle is always equal to the sum of the interior opposite angles.

    ∠ADC + ∠ACD = ∠BAC (given ,∠BAC = 50°)

    ∠ADC + ∠ADC = 50°

    2 ∠ ADC = 50°

    ∠ ADC = 25°
    Step 2:- find  ∠ACB
    From diagram ,

    ∠ACB = ∠BCD - ∠ACD (given ∠BCD = 80°)

    ∠ACB = 80°- 25°

    ∴∠ACB = 55°
    Step 3:-Find  ∠DBC

    In straight capital delta ABC ,

    ∠BAC + ∠ABC + ∠ACB = 180°(sum of angles in the triangle)

    (given, ∠BAC= 50° and we got ∠ACB = 55°)

    ∠ ABC + 50°+ 55° = 180°

    ∠ ABC = 180°- 105°

    ∴ ∠ ABC = 75°

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