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Maths-

General

Easy

Question

$integral fraction numerator d x over denominator square root of x squared plus 2 x plus 1 end root end fraction$ = A log |x + 1| + C for x < – 1 then A is -

0
1
-1
none

The correct answer is: 1

$fraction numerator d x over denominator square root of left parenthesis x plus 1 right parenthesis squared end root end fraction equals integral fraction numerator d x over denominator vertical line x plus 1 vertical line end fraction equals log invisible function application vertical line x plus 1 vertical line plus C$

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