Maths-
General
Easy

Question

Jeremy deposited x dollars in his investment account on January 1, 2001. The amount of money in the account doubled each year until Jeremy had 480 dollars in his investment account on January 1,2005 . What is the value of x ?

hintHint:

Hint:
  • Here we will first make equation using the given condition and then solve it.

The correct answer is: The value of x is 30.


    Explanation:
    • We have given the amount of money in the account doubled each year until Jeremy had 480 dollars.
    • We have to find the value of x.
    Step 1 of 1:
    Jeremy deposited  dollar and gets double of his deposited for each year until  he had 480.
    For y number of years the above statement can be written as:
    x open parentheses 2 to the power of y close parentheses equals 480
    Where y is the number of years  between January 1, 2005 and
    January 1, 2001
    x is his initial deposit
    y equals 2005 minus 2001 equals 4
    from the equation above, divide both sides by 2y,
    x equals 480 divided by 2 to the power of y
    x equals 480 divided by 2 to the power of 4
    x equals 480 divided by 16
    x = 30
    Hence, The value of x is 30.

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