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Question

L subscript left parenthesis t rightwards arrow 2 right parenthesis left parenthesis vertical line x minus 2 vertical line right parenthesis divided by left parenthesis x minus 2 right parenthesis

  1. -1
  2. 1
  3. 0
  4. 2

hintHint:

The given function is modulus function so we will calculate Left hand limit (LHL) and Right Hand limit (RHL).

The correct answer is: -1


    In this question we have to find
    limit as t minus greater than 2 of fraction numerator open vertical bar x minus 2 close vertical bar over denominator x minus 2 end fraction. We are given modulus function. So, we have to check limit in the neighborhood of 2
    Step1: Checking limit at t minus greater than 2 to the power of plus. That is Right Hand Limit
    limit as t minus greater than 2 to the power of plus of fraction numerator open vertical bar x minus 2 close vertical bar over denominator x minus 2 end fraction
    Since, x greater than 2 comma space open vertical bar x minus 2 close vertical bar equals x minus 2
    limit as t minus greater than 2 to the power of plus of fraction numerator x minus 2 over denominator x minus 2 end fraction
    =>limit as t minus greater than 2 to the power of plus of fraction numerator x minus 2 over denominator x minus 2 end fraction equals 1
    Step2: Checking Left hand limit
    limit as t minus greater than 2 to the power of minus of fraction numerator open vertical bar x minus 2 close vertical bar over denominator x minus 2 end fraction
    Since, x less than 2 comma space open vertical bar x minus 2 close vertical bar equals space minus left parenthesis x minus 2 right parenthesis
    limit as t minus greater than 2 to the power of minus of fraction numerator negative left parenthesis x minus 2 right parenthesis over denominator x minus 2 end fraction
    => limit as t minus greater than 2 to the power of minus of fraction numerator negative left parenthesis x minus 2 right parenthesis over denominator x minus 2 end fraction equals negative 1
    Since both left and Right hand limit are not same the function is not continuous at x equals 2

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