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Maths-

General

Easy

Question

‘0’ is the centre of the circle and $B A C plus B O C equals 120 to the power of ring operator end exponent text then end text angle C O B equals$

30°
80°
60°
120°

The correct answer is: 60°

$angle B O C equals angle 2 B A C space left parenthesis space T h e space a n g l e space s u b t e n d e d space b y space a n space a r c space a t space t h e space c e n t e r space i s space d o u b l e space t h e space a n g l e space s u b t e n d e d space b y space i t space a t space a n y space p o i n t space o n space t h e space r e m a i n i n g space p a r t space o f space t h e space c i r c l e right parenthesis L e t space angle B A C equals x t h e n space space angle B O C equals 2 x x plus 2 x equals 120 to the power of ring operator 3 x equals 120 to the power of ring operator x equals 40 to the power of ring operator C O B equals 80 to the power of ring operator$

Related Questions to study

In the given diagram $fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction$ and $A B equals 5 c m.$ Find the value of DC.

In the given diagram $fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction$ and $A B equals 5 c m.$ Find the value of DC.

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parallel

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