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Question

Domain of the function f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of l n invisible function application c o t to the power of negative 1 end exponent invisible function application x end root end fraction is

  1. left parenthesis c o t invisible function application 1 comma infinity right parenthesis    
  2. R minus left curly bracket c o t invisible function application 1 right curly bracket    
  3. open parentheses negative infinity subscript 4 end subscript 0 close parentheses union left parenthesis 0 comma c o t invisible function application 1 right parenthesis    
  4. left parenthesis negative infinity comma c o t invisible function application 1 right parenthesis    

The correct answer is: left parenthesis negative infinity comma c o t invisible function application 1 right parenthesis


    table row cell l n invisible function application open parentheses cot to the power of negative 1 end exponent invisible function application x close parentheses greater than 0 end cell row cell c o t to the power of negative 1 end exponent invisible function application x greater than 1 end cell row cell x less than c o t invisible function application 1 end cell row cell therefore text end text text d end text text o end text text m end text text a end text text i end text text n end text text end text left parenthesis negative infinity comma c o t invisible function application 1 right parenthesis end cell end table

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