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Maths-

General

Easy

Question

The domain of the function $f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of vertical line t a n invisible function application x vertical line minus t a n invisible function application x end root end fraction$ is

$(n π, n π + \frac{π}{2}), n \in I$
$(n π + \frac{π}{2}, n π + π), n \in I$
$(2 n π, 2 n π + \frac{π}{2}), n \in I$
none of these

The correct answer is: $open parentheses n pi plus fraction numerator pi over denominator 2 end fraction comma n pi plus pi close parentheses comma n element of I$

$table row cell text end text text F end text text o end text text r end text text end text f left parenthesis x right parenthesis text end text text t end text text o end text text end text text b end text text e end text text end text text d end text text e end text text f end text text i end text text n end text text e end text text d end text text end text vertical line t a n invisible function application x vertical line minus t a n invisible function application x greater than 0 end cell row cell rightwards double arrow open vertical bar tan invisible function application x close vertical bar greater than tan invisible function application x rightwards double arrow tan invisible function application x less than 0 end cell row cell rightwards double arrow n pi plus fraction numerator pi over denominator 2 end fraction less than x less than n pi plus pi end cell row cell left square bracket text end text text s end text text i end text text n end text text c end text text e end text text end text text p end text text e end text text r end text text i end text text o end text text d end text text end text text o end text text f end text text end text t a n invisible function application x text end text text i end text text s end text text end text pi right square bracket end cell end table$

Related Questions to study

The domain of definition of the function $Error converting from MathML to accessible text.$

The domain of definition of the function $Error converting from MathML to accessible text.$

Let $f colon left square bracket negative 1 , 1 right square bracket rightwards arrow R$ be a function defined as $y equals f left parenthesis x right parenthesis text and end text g left parenthesis x right parenthesis equals l o g subscript 2 e end subscript invisible function application left square bracket x right square bracket$ ; ([.] denotes greatest integer function) then number of integers in the domain of f (g(x)) is/are

Let $f colon left square bracket negative 1 , 1 right square bracket rightwards arrow R$ be a function defined as $y equals f left parenthesis x right parenthesis text and end text g left parenthesis x right parenthesis equals l o g subscript 2 e end subscript invisible function application left square bracket x right square bracket$ ; ([.] denotes greatest integer function) then number of integers in the domain of f (g(x)) is/are

Statement - I : Let f(x) be a function such that $f left parenthesis x minus 1 right parenthesis plus f left parenthesis x plus 1 right parenthesis equals square root of 2 f left parenthesis x right parenthesis$ for all x $element of$ R then f is periodic
Statement - II : There exists a function with period 8

Statement - I : Let f(x) be a function such that $f left parenthesis x minus 1 right parenthesis plus f left parenthesis x plus 1 right parenthesis equals square root of 2 f left parenthesis x right parenthesis$ for all x $element of$ R then f is periodic
Statement - II : There exists a function with period 8

parallel

An ellipse has foci at (9, 20) and (49, 55) in the xy-plane and is tangent to the x axis. The length of its major axis is :

An ellipse has foci at (9, 20) and (49, 55) in the xy-plane and is tangent to the x axis. The length of its major axis is :

If the ellipse $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent minus 3 end fraction minus fraction numerator y to the power of 2 end exponent over denominator a plus 4 end fraction equals 1$ is inscribed in square of side length $a square root of 2 comma$ then a is

If the ellipse $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent minus 3 end fraction minus fraction numerator y to the power of 2 end exponent over denominator a plus 4 end fraction equals 1$ is inscribed in square of side length $a square root of 2 comma$ then a is

The area of the quadrilateral formed by the tangents at the ends of latus-rectum of $5 x to the power of 2 end exponent plus 9 y to the power of 2 end exponent equals 45$ is

The area of the quadrilateral formed by the tangents at the ends of latus-rectum of $5 x to the power of 2 end exponent plus 9 y to the power of 2 end exponent equals 45$ is

parallel

In the standard ellipse, the lines joining the ends of the minor axis to one focus are at right angles. The distance between the focus and the nearer vertex is $square root of 10 minus square root of 5$ The equation of the ellipse

In the standard ellipse, the lines joining the ends of the minor axis to one focus are at right angles. The distance between the focus and the nearer vertex is $square root of 10 minus square root of 5$ The equation of the ellipse

Three metal ions x⁺², y⁺², z⁺² are identify in qualitative analysis. Nitrates of x⁺², y⁺², z⁺² dissolve in three seprate test tubes and gives following observation.
i) All solution produce carbonate precipitate with (NH₄)₂CO₃
ii) Only one produce white ppt on addition of NaCl.
iii) Out of 3 cations two produce sulphide ppt.
iv) Sulphide of y⁺² is not produce by H₂S/H⁺but produce when H₂S is passed in basic medium.
v) Only y⁺² produce soluble sulphate
vi) x ⁺² gives no ppt with dil NH₄OH
Select correct about xCO₃ , y CO₃ , z CO₃ -

Three metal ions x⁺², y⁺², z⁺² are identify in qualitative analysis. Nitrates of x⁺², y⁺², z⁺² dissolve in three seprate test tubes and gives following observation.
i) All solution produce carbonate precipitate with (NH₄)₂CO₃
ii) Only one produce white ppt on addition of NaCl.
iii) Out of 3 cations two produce sulphide ppt.
iv) Sulphide of y⁺² is not produce by H₂S/H⁺but produce when H₂S is passed in basic medium.
v) Only y⁺² produce soluble sulphate
vi) x ⁺² gives no ppt with dil NH₄OH
Select correct about xCO₃ , y CO₃ , z CO₃ -

chemistry-General

Read the following comprehension carefully and answer the following questions

Read the following comprehension carefully and answer the following questions

chemistry-General

parallel

Read the following comprehension carefully and answer the following questions

The compound

Read the following comprehension carefully and answer the following questions

The compound

chemistry-General

Read the following comprehension carefully and answer the following questions

Yellow solution (C) is an important laboratory reagent and is used in the estimation of :

Read the following comprehension carefully and answer the following questions

Yellow solution (C) is an important laboratory reagent and is used in the estimation of :

chemistry-General

Read the following comprehension carefully and answer the following questions

The colour of the ppt (D) & (E) are :

Read the following comprehension carefully and answer the following questions

The colour of the ppt (D) & (E) are :

chemistry-General

parallel

Moreover, the salt 'A' on heating with solid K₂Cr₂O₇ and concentrated H₂SO₄ produces deep red vapours which dissolve in sodium hydroxide solution forming a yellow solution. This yellow solution gives yellow precipitate with Ba(NO₃ ) ₂ solution. On the basis of the aforesaid characteristic informations answer the following questions :
Select the correct statement.

Moreover, the salt 'A' on heating with solid K₂Cr₂O₇ and concentrated H₂SO₄ produces deep red vapours which dissolve in sodium hydroxide solution forming a yellow solution. This yellow solution gives yellow precipitate with Ba(NO₃ ) ₂ solution. On the basis of the aforesaid characteristic informations answer the following questions :
Select the correct statement.

chemistry-General

Statement-1 : Nessler’s reagent gives a brown precipitate with aqueous ammonia as well as with ammonium salts. Statement-2 : Aqueous ammonia gives a brown precipitate with a solution of manganese (II) chloride and hydrogen peroxide.

Statement-1 : Nessler’s reagent gives a brown precipitate with aqueous ammonia as well as with ammonium salts. Statement-2 : Aqueous ammonia gives a brown precipitate with a solution of manganese (II) chloride and hydrogen peroxide.

chemistry-General

Statement-1 : A solution containing S^2– ions gives purple / violet colour with sodium nitroprusside solution in alkaline medium.
Statement-2 : Sodium sulphide gives black precipitate with silver nitrate solution.

Statement-1 : A solution containing S^2– ions gives purple / violet colour with sodium nitroprusside solution in alkaline medium.
Statement-2 : Sodium sulphide gives black precipitate with silver nitrate solution.

chemistry-General

parallel

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