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Maths-

General

Easy

Question

From the figure, $stack P Q with bar on top parallel to stack R S with bar on top text and end text stack P S with bar on top parallel to stack Q R with bar on top$ Then ( x – y)

30°
–30°
40°
–40°

The correct answer is: –30°

x+2y =180 (complementary angles)

$angle Q P T plus angle Q P S space equals space 180 140 space plus angle Q P S space equals 180 angle Q P S equals 40$
Also

$angle Q P S plus angle R S P equals 180 space left parenthesis s u p p l e m e n t a r y space a n g l e s right parenthesis 40 plus 2 y space equals 180 2 y equals 180 minus 40 y equals 140 divided by 2 y equals 70$
Also x+2y = 180
x+140 = 180
x= 180-140
x =40 degree

Related Questions to study

In the figure, if $angle 3 colon angle 6 equals 2 colon 7 text then end text angle 2 colon angle 7 equals$

In the figure, if $angle 3 colon angle 6 equals 2 colon 7 text then end text angle 2 colon angle 7 equals$

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angle on a straight line is always 180⁰

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angle on a straight line is always 180⁰

In the figure, n is transversal to $l comma m$ then $left parenthesis x plus y plus z right parenthesis minus left parenthesis p plus q plus r right parenthesis equals ?$

In the figure, n is transversal to $l comma m$ then $left parenthesis x plus y plus z right parenthesis minus left parenthesis p plus q plus r right parenthesis equals ?$

parallel

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Angle in complete circle is 360^₀

According to the data given in figure, x = ?

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Find the value of x from the following Venn diagram if

In Venn diagram, $left parenthesis A intersection C right parenthesis union left parenthesis B intersection C right parenthesis equals$

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intersection of superset with subset is subset

S₁ : Generally square planar complexes show geometrical isomerism but do not exhibit optical isomerism because they do not possess planer of symmetry.
S₂ : $capital delta subscript t end subscript equals fraction numerator 4 over denominator 9 end fraction capital delta subscript 0 end subscript$
S₃ : In octahedral complexes each electron entering the t_2g orbitals stabilizes the complex ion by 0.4 $capital delta subscript 0 end subscript$ and each electron entering the e.gorbital destabilizes the complex by an amount of 0.6 Δ₀.

S₁ : Generally square planar complexes show geometrical isomerism but do not exhibit optical isomerism because they do not possess planer of symmetry.
S₂ : $capital delta subscript t end subscript equals fraction numerator 4 over denominator 9 end fraction capital delta subscript 0 end subscript$
S₃ : In octahedral complexes each electron entering the t_2g orbitals stabilizes the complex ion by 0.4 $capital delta subscript 0 end subscript$ and each electron entering the e.gorbital destabilizes the complex by an amount of 0.6 Δ₀.

chemistry-General

parallel

All the following complex show decreases in their weights when placed in a magnetic balance then the group of complexes having tetrahedral geometry is :
i) Ni(CO)₄
ii) K[AgF₄ ]
iii) Na₂ [Zn(CN)₄ ]
iv) K₂ [PtCl₄ ]
v) [RhCl(PPh₃)₃ ]

All the following complex show decreases in their weights when placed in a magnetic balance then the group of complexes having tetrahedral geometry is :
i) Ni(CO)₄
ii) K[AgF₄ ]
iii) Na₂ [Zn(CN)₄ ]
iv) K₂ [PtCl₄ ]
v) [RhCl(PPh₃)₃ ]

chemistry-General

$N i C l subscript 2 end subscript stack stack ⟶ with K C N on top with H C N below$ complex A
$N i C l subscript 2 end subscript stack stack ⟶ with K C l on top with text excess end text below$ complex B
A & B complexes have the co-ordination number 4.
The IUPAC name of complexes ‘A’ & ‘B’ are respectively :

$N i C l subscript 2 end subscript stack stack ⟶ with K C N on top with H C N below$ complex A
$N i C l subscript 2 end subscript stack stack ⟶ with K C l on top with text excess end text below$ complex B
A & B complexes have the co-ordination number 4.
The IUPAC name of complexes ‘A’ & ‘B’ are respectively :

chemistry-General

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chemistry-General

parallel

How many EDTA (ethylenediaminetetraacetic acid) molecules are required to make an octahedral complex with a Ca2+ ion ?

How many EDTA (ethylenediaminetetraacetic acid) molecules are required to make an octahedral complex with a Ca2+ ion ?

chemistry-General

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In Fe(CO)₅, the Fe – C bond possesses :

chemistry-General

When degenerate d-orbitals of an iSol. ated atom/ion come under influence of magnetic field of ligands, the degeneracy is lost The two set $t subscript 2 g end subscript open parentheses d subscript x y end subscript comma d subscript y z end subscript comma d subscript x z end subscript close parentheses$ and $open parentheses d subscript z to the power of 2 end exponent end subscript comma d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript close parentheses$ are either stabilized or destrabilized depending upon the nature of magnetic fieldIt can be expressed diagrammatically as:
Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for $capital delta$ is about 4/9 times to $capital delta subscript 0 end subscript$ tetrahedral complexes, (CFSE for octahedral complex)This energy lies in visible region and i.e., why electronic transition are responsible for colour Such transitions are not possible with d0 and d10 configuration.
Crystal field stabilization energy for [ $open square brackets C o F subscript 6 end subscript close square brackets to the power of 3 minus end exponent$ in terms of parameter Dq is – $left parenthesis capital delta equals 10 D q right parenthesis$

When degenerate d-orbitals of an iSol. ated atom/ion come under influence of magnetic field of ligands, the degeneracy is lost The two set $t subscript 2 g end subscript open parentheses d subscript x y end subscript comma d subscript y z end subscript comma d subscript x z end subscript close parentheses$ and $open parentheses d subscript z to the power of 2 end exponent end subscript comma d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript close parentheses$ are either stabilized or destrabilized depending upon the nature of magnetic fieldIt can be expressed diagrammatically as:
Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for $capital delta$ is about 4/9 times to $capital delta subscript 0 end subscript$ tetrahedral complexes, (CFSE for octahedral complex)This energy lies in visible region and i.e., why electronic transition are responsible for colour Such transitions are not possible with d0 and d10 configuration.
Crystal field stabilization energy for [ $open square brackets C o F subscript 6 end subscript close square brackets to the power of 3 minus end exponent$ in terms of parameter Dq is – $left parenthesis capital delta equals 10 D q right parenthesis$

chemistry-General

parallel

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