Given O is center of smaller Circle, BD is common chord, ABC, EDO are straight lines. If AED =130°, then C O D =

maths-

From the figure $left floor P B R equals$

maths-General

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if $stack ∣ O A B with _ below$ = 35° then $left floor E B C equals$

Here we used the concept of angle sum property of a triangle. When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. So here the angle EBC is 35 degree.

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if $stack ∣ O A B with _ below$ = 35° then $left floor E B C equals$

chemistry-

About 2 to 5% of gypsum $left parenthesis C a S O subscript 4.2 H subscript 2 O right parenthesis$ is added to Portland cement. It is just to

chemistry-General

If $sec to the power of 4 space theta plus sec squared space theta equals 10 plus tan to the power of 4 space theta plus tan squared space theta text then end text sin squared text end text theta$ =

biology

Osmosis is the phenomenon expressed by :

biologyGeneral

If $4 n alpha equals pi comma$ then the numerical value of $tan space alpha tan space 2 alpha tan space 3 alpha horizontal ellipsis horizontal ellipsis tan space left parenthesis 2 n minus 1 right parenthesis alpha$ is equal to

$3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator space$ =

$sin space 20 to the power of ring operator open parentheses 4 plus sec space 20 to the power of ring operator close parentheses$ =

In the figure $P Q greater than P R comma$ QS and RS are the bisectors of $stack ∣ Q with _ below$ and $stack R with _ below$ respectively then

If AB=AC and $A C D equals 115 to the power of ring operator end exponent$ then $stack B with _ below A C equals$

Here we used the concept of linear pair. When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. So here the angle A is 50 degree.

If AB=AC and $A C D equals 115 to the power of ring operator end exponent$ then $stack B with _ below A C equals$

In the figure $A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent$ then ACD=

Here we used the concept of linear pair and exterior angle property. When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. So here the angle BCD is 110 degrees.

In the figure $A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent$ then ACD=

$open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses$ =

If $tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction$ and $tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root$ then $alpha plus beta$ =

If $tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi sin space theta right parenthesis comma 0 less than theta less than fraction numerator 3 pi over denominator 4 end fraction$ then $sin space open parentheses theta plus pi over 4 close parentheses equals$