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Question

If a not equal to 0 and the line 2bx + 3cy + 4d = 0 passes through the points of intersection of the parabolas y2 = 4ax and x2 = 4ay, then

  1. d2 + (3b – 2c)2 = 0    
  2. d2 + (3b + 2c)2 = 0    
  3. d2 + (2b – 3c)2 = 0    
  4. d2 + (2b + 3c)2 = 0    

The correct answer is: d2 + (2b + 3c)2 = 0


    The two parabolas intersect at (0, 0) and (4a, 4a). The equation of their common chord must be y = x which must be same as given line
    2bx + 3ay + 4d = 0
    table row cell rightwards double arrow 2 b equals negative 3 c comma d equals 0 end cell row cell rightwards double arrow left parenthesis 2 b plus 3 c right parenthesis to the power of 2 end exponent plus d to the power of 2 end exponent equals 0 end cell end table

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