Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If A = $open square brackets table row alpha 0 row 1 1 end table close square brackets$ , B = $open square brackets table row 1 0 row 5 1 end table close square brackets$ and A² = B, then

Statement is not true for any real value of
$α$ =1
$α$ = –1
$α$ = 4

The correct answer is: Statement is not true for any real value of

Related Questions to study

Let A be a square matrix all of whose entries are integers. Then which one of the following is true ?

Let A be a square matrix all of whose entries are integers. Then which one of the following is true ?

Let A = $open square brackets table row 5 cell 5 alpha end cell alpha row 0 alpha cell 5 alpha end cell row 0 0 5 end table close square brackets$ If |A2| = 25, then | $alpha$ | equals

Let A = $open square brackets table row 5 cell 5 alpha end cell alpha row 0 alpha cell 5 alpha end cell row 0 0 5 end table close square brackets$ If |A2| = 25, then | $alpha$ | equals

Let A = $open parentheses table row 1 2 row 3 4 end table close parentheses$ and B = $open parentheses table row a 0 row 0 b end table close parentheses$ , a, b $element of$ N. Then

Let A = $open parentheses table row 1 2 row 3 4 end table close parentheses$ and B = $open parentheses table row a 0 row 0 b end table close parentheses$ , a, b $element of$ N. Then

parallel

If A and B are square matrices of size n × n such that A² – B² = (A – B) (A + B), then which of the following will be always true –

If A and B are square matrices of size n × n such that A² – B² = (A – B) (A + B), then which of the following will be always true –

If A = $open square brackets table row 1 0 row 1 1 end table close square brackets$ and I = $open square brackets table row 1 0 row 0 1 end table close square brackets$ , then which one of the following holds for all n $greater or equal than$ 1, by the principle of mathematical induction -

If A = $open square brackets table row 1 0 row 1 1 end table close square brackets$ and I = $open square brackets table row 1 0 row 0 1 end table close square brackets$ , then which one of the following holds for all n $greater or equal than$ 1, by the principle of mathematical induction -

If A² – A + I = 0, then the inverse of A is

If A² – A + I = 0, then the inverse of A is

parallel

Let A = $open parentheses table row 1 cell negative 1 end cell 1 row 2 1 cell negative 3 end cell row 1 1 1 end table close parentheses$ and (10) B = $open parentheses table row 4 2 2 row cell negative 5 end cell 0 alpha row 1 cell negative 2 end cell 3 end table close parentheses$ . If B is the inverse of matrix A, then $alpha$ is

Let A = $open parentheses table row 1 cell negative 1 end cell 1 row 2 1 cell negative 3 end cell row 1 1 1 end table close parentheses$ and (10) B = $open parentheses table row 4 2 2 row cell negative 5 end cell 0 alpha row 1 cell negative 2 end cell 3 end table close parentheses$ . If B is the inverse of matrix A, then $alpha$ is

Let A = $open parentheses table row 0 0 cell negative 1 end cell row 0 cell negative 1 end cell 0 row cell negative 1 end cell 0 0 end table close parentheses$ . The only correct statement about the matrix A is

Let A = $open parentheses table row 0 0 cell negative 1 end cell row 0 cell negative 1 end cell 0 row cell negative 1 end cell 0 0 end table close parentheses$ . The only correct statement about the matrix A is

Bleaching powder has the molecular formula:

Bleaching powder has the molecular formula:

chemistry-General

parallel

If A = $open square brackets table row a b row b a end table close square brackets$ and A² = $open square brackets table row alpha beta row beta alpha end table close square brackets$ , then

If A = $open square brackets table row a b row b a end table close square brackets$ and A² = $open square brackets table row alpha beta row beta alpha end table close square brackets$ , then

If A= $open square brackets table row 1 2 3 row 3 1 2 row 2 3 1 end table close square brackets$ , B = $open square brackets table row cell negative 5 end cell 7 1 row 1 cell negative 5 end cell 7 row 7 1 cell negative 5 end cell end table close square brackets$ then AB =

If A= $open square brackets table row 1 2 3 row 3 1 2 row 2 3 1 end table close square brackets$ , B = $open square brackets table row cell negative 5 end cell 7 1 row 1 cell negative 5 end cell 7 row 7 1 cell negative 5 end cell end table close square brackets$ then AB =

If A = $open square brackets table row i 0 row 0 cell negative i end cell end table close square brackets$ , B = $open square brackets table row 0 cell negative 1 end cell row 1 0 end table close square brackets$ and C = $open square brackets table row 0 i row i 0 end table close square brackets$ , then A² = B²=C² =

If A = $open square brackets table row i 0 row 0 cell negative i end cell end table close square brackets$ , B = $open square brackets table row 0 cell negative 1 end cell row 1 0 end table close square brackets$ and C = $open square brackets table row 0 i row i 0 end table close square brackets$ , then A² = B²=C² =

parallel

If Ai = $open square brackets table row cell a to the power of i end exponent end cell cell b to the power of i end exponent end cell row cell b to the power of i end exponent end cell cell a to the power of i end exponent end cell end table close square brackets$ and if |a|<1, |b|<1, then $not stretchy sum subscript i equals 1 end subscript superscript infinity end superscript blank$ det (A_i) is equal to-

If Ai = $open square brackets table row cell a to the power of i end exponent end cell cell b to the power of i end exponent end cell row cell b to the power of i end exponent end cell cell a to the power of i end exponent end cell end table close square brackets$ and if |a|<1, |b|<1, then $not stretchy sum subscript i equals 1 end subscript superscript infinity end superscript blank$ det (A_i) is equal to-

If matrix A = $open square brackets table row 1 0 cell negative 1 end cell row 3 4 5 row 0 6 7 end table close square brackets$ and its inverse is denoted by $A to the power of negative 1 end exponent equals open square brackets table row cell a subscript 11 end subscript end cell cell a subscript 12 end subscript end cell cell a subscript 13 end subscript end cell row cell a subscript 21 end subscript end cell cell a subscript 22 end subscript end cell cell a subscript 23 end subscript end cell row cell a subscript 31 end subscript end cell cell a subscript 32 end subscript end cell cell a subscript 33 end subscript end cell end table close square brackets$ , then the value of a₂₃is equal to-

If matrix A = $open square brackets table row 1 0 cell negative 1 end cell row 3 4 5 row 0 6 7 end table close square brackets$ and its inverse is denoted by $A to the power of negative 1 end exponent equals open square brackets table row cell a subscript 11 end subscript end cell cell a subscript 12 end subscript end cell cell a subscript 13 end subscript end cell row cell a subscript 21 end subscript end cell cell a subscript 22 end subscript end cell cell a subscript 23 end subscript end cell row cell a subscript 31 end subscript end cell cell a subscript 32 end subscript end cell cell a subscript 33 end subscript end cell end table close square brackets$ , then the value of a₂₃is equal to-

For the matrix A = $open square brackets table row 1 1 0 row 1 2 1 row 2 1 0 end table close square brackets$ , which of the following is correct

For the matrix A = $open square brackets table row 1 1 0 row 1 2 1 row 2 1 0 end table close square brackets$ , which of the following is correct

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.