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Question

If f(x) is a polynomial of degree five with leading coefficient one such that  f(1)=12,f(2)=22,f(3)=32,f(4)=42,f(5)=52 then

  1. f(6)= 156    
  2. stack lim with x rightwards arrow infinity below invisible function application open parentheses fraction numerator f left parenthesis x right parenthesis over denominator x to the power of 5 end exponent end fraction close parentheses    
  3. f(0)less than0    
  4. f(0)greater than0    

The correct answer is: f(6)= 156


    f left parenthesis x right parenthesis minus x to the power of 2 end exponent equals left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis left parenthesis x minus 3 right parenthesis left parenthesis x minus 4 right parenthesis left parenthesis x minus 5

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