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Maths-

General

Easy

Question

If for $A X equals B comma$ $B equals open square brackets table row cell 9 end cell row cell 52 end cell row cell 0 end cell end table close square brackets$ and $A to the power of negative 1 end exponent equals open square brackets table row 3 cell negative fraction numerator 1 over denominator 2 end fraction end cell cell negative fraction numerator 1 over denominator 2 end fraction end cell row cell negative 4 end cell cell rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow fraction numerator 3 over denominator 4 end fraction end cell cell fraction numerator 5 over denominator 4 end fraction end cell row 2 cell negative fraction numerator 1 over denominator 4 end fraction end cell cell negative fraction numerator 3 over denominator 4 end fraction end cell end table close square brackets$ ,then X is equal to

$[\begin{matrix} 1 \\ 3 \\ 5 \end{matrix}]$
$[\begin{matrix} - \frac{1}{2} \\ - \frac{1}{2} \\ 2 \end{matrix}]$
$[\begin{matrix} - 4 \\ 2 \\ 3 \end{matrix}]$
$[\begin{matrix} 3 \\ \begin{matrix} \frac{3}{4} \\ - \frac{3}{4} \end{matrix} \end{matrix}]$

The correct answer is: $open square brackets table row cell 1 end cell row cell 3 end cell row cell 5 end cell end table close square brackets$

$A X equals B rightwards double arrow A to the power of negative 1 end exponent. A X equals A to the power of negative 1 end exponent B rightwards double arrow X equals A to the power of negative 1 end exponent B equals open square brackets table row cell 1 end cell row cell 3 end cell row cell 5 end cell end table close square brackets$ .

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