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Maths-

General

Easy

Question

If m and $sigma to the power of 2 end exponent$ are the mean and variance of the random variable X, whose distribution is given by:

$m = σ^{2} = 2$
$m = 1, σ^{2} = 2$
$m = σ^{2} = 1$
$m = 2, σ^{2} = 1$

The correct answer is: $m equals sigma to the power of 2 end exponent equals 1$

$mu equals capital sigma x subscript i end subscript P open parentheses X equals x subscript i end subscript close parentheses comma V left parenthesis x right parenthesis equals capital sigma x subscript i end subscript superscript 2 end superscript P open parentheses X equals x subscript 1 end subscript close parentheses minus mu to the power of 2 end exponent$

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