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Maths-

General

Easy

Question

If the matrix $open square brackets table row 1 3 cell alpha plus 2 end cell row 2 4 8 row 3 5 10 end table close square brackets$ is singular, then $alpha$ =

– 4
4
2
– 2

The correct answer is: 4

|A| = 0
$open vertical bar table row 1 3 cell alpha plus 2 end cell row 2 4 8 row 3 5 10 end table close vertical bar$ = 0
1(0) –3 (20–24) + ( $alpha$ + 2) (–2) = 0
12 – 2 $alpha$ – 4 = 0 $rightwards double arrow$ $alpha$ = 4

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