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Maths-

General

Easy

Question

Let $f left parenthesis x right parenthesis equals fraction numerator ln invisible function application x over denominator x end fraction for all x greater than 0 comma$ then
Statement-1: $f open parentheses fraction numerator 5 over denominator 2 end fraction close parentheses greater than f open parentheses fraction numerator 9 over denominator 2 end fraction close parentheses$ because
Statement 2 : $f open parentheses x subscript 1 end subscript close parentheses greater than f open parentheses x subscript 2 end subscript close parentheses for all x subscript 1 end subscript element of open parentheses 2 comma 4 close parentheses text and end text x subscript 2 end subscript element of open parentheses 0 comma 2 close parentheses union open parentheses 4 comma infinity close parentheses$

Statement-1is True, Statement-2 is True;Statement-2 is a correct explanation for Statement-1
Statement-1 is True, Statement-2 is True;Statement-2 is not a correct explanation
Statement -1 is True, Statement -2 is False
Statement -1 is False, Statement -2 is True

The correct answer is: Statement-1is True, Statement-2 is True;Statement-2 is a correct explanation for Statement-1

Related Questions to study

If f(x) is a polynomial function such that $f open parentheses x close parentheses f open parentheses fraction numerator 1 over denominator x end fraction close parentheses equals f open parentheses x close parentheses plus f open parentheses fraction numerator 1 over denominator x end fraction close parentheses$ for all non zero real values of x and f(4) = -15 then f(3) + f(-3) =

If f(x) is a polynomial function such that $f open parentheses x close parentheses f open parentheses fraction numerator 1 over denominator x end fraction close parentheses equals f open parentheses x close parentheses plus f open parentheses fraction numerator 1 over denominator x end fraction close parentheses$ for all non zero real values of x and f(4) = -15 then f(3) + f(-3) =

The total number of solutions of $left square bracket x right square bracket to the power of 2 end exponent equals x plus 2 open curly brackets x close curly brackets comma$ where [.] and {.} denote greatest integer function and fractional part, respectively is equal to

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Let $f left parenthesis x right parenthesis equals x left square bracket x right square bracket$ where $left square bracket x right square bracket$ denotes the greatest integer smaller than or equal to x. When x is not an integer, what is f’ (x) ?

Let $f left parenthesis x right parenthesis equals x left square bracket x right square bracket$ where $left square bracket x right square bracket$ denotes the greatest integer smaller than or equal to x. When x is not an integer, what is f’ (x) ?

parallel

For $x comma y element of R comma f left parenthesis x plus y right parenthesis equals f left parenthesis x right parenthesis f left parenthesis y right parenthesis$ with f(1) = 2 If $stretchy sum from k equals 1 to n of f left parenthesis a plus k right parenthesis equals 480 comma$ then the ordered pair (a, n) is

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Let $f left parenthesis x right parenthesis equals m a x times left curly bracket 1 plus s i n invisible function application x comma 1 minus c o s invisible function application x right curly bracket comma x element of left square bracket 0 comma 2 pi right square bracket$ and $g left parenthesis x right parenthesis equals m a x times left curly bracket 1 comma vertical line x minus 1 vertical line right curly bracket for all x element of R comma$ then

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A = (1,2,3,4,5), B = (1,2,3,4) and $f colon A @ B$ is a function. Then

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Which graphs best represents the relationship obtained when y is
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physics-General

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physics-General

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physics-General

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