Question
Statement-I : If a, b, c are three distinct positive number in H.P., then
Statement-II : Sum of any number and it's reciprocal is always greater than or equal to 2.
- Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I.
- Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-I.
- Statement-I is true, Statement-II is false.
- Statement-I is false, Statement-II is true.
Hint:
use the definition of HP to check the validity of statement 1. statement 2 is false.
The correct answer is: Statement-I is false, Statement-II is true.
Statement-I is true, Statement-II is false.
a, b ,c are in HP
1/a , 1/b ,1/c are in AP
(1/b +1/a)/(2/b-1/a) +(1/b+1/c)/(2/b-1/c)= (1/b +1/a)/(1/c) + (1/b+1/c)/(1/a)
On solving , we get
½(a/c+c/a +2)+(c/a +a/c)
We know that a+ 1/a > 2 when a > 0
Therefore, the above expression gives uus
½(2+2)+(2) > 4.
Hence, the statement 1 is true but the statement 2 is false.
when some numbers are in HP, then their reciprocals are in AP.
Related Questions to study
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Statement-I : In any ΔABC, maximum value of r1 + r2 + r3 =9R/2.
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