Maths-
General
Easy

Question

Statement-I : If a, b, c are three distinct positive number in H.P., then open parentheses fraction numerator a plus b over denominator 2 a minus b end fraction close parentheses plus open parentheses fraction numerator c plus b over denominator 2 c minus b end fraction close parentheses greater than 4
Statement-II : Sum of any number and it's reciprocal is always greater than or equal to 2.

  1. Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I.    
  2. Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-I.    
  3. Statement-I is true, Statement-II is false.    
  4. Statement-I is false, Statement-II is true.    

hintHint:

use the definition of HP to check the validity of statement 1. statement 2 is false.

The correct answer is: Statement-I is false, Statement-II is true.



    Statement-I is true, Statement-II is false.
    a, b ,c are in HP
    1/a , 1/b ,1/c are in AP
    (1/b +1/a)/(2/b-1/a) +(1/b+1/c)/(2/b-1/c)= (1/b +1/a)/(1/c) + (1/b+1/c)/(1/a)
    On solving , we get
    ½(a/c+c/a +2)+(c/a +a/c)
    We know that a+ 1/a > 2 when a > 0
    Therefore, the above expression gives uus
    ½(2+2)+(2) > 4.
    Hence, the statement 1 is true but the statement 2 is false.

    when some numbers are in HP, then their reciprocals are in AP.

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