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Question

Statement-I : If x subscript n end subscript equals c o s invisible function application open parentheses pi divided by 2 to the power of n end exponent close parentheses plus i s i n invisible function application open parentheses pi divided by 2 to the power of n end exponent close parentheses then x subscript 1 end subscript times x subscript 2 end subscript times x subscript 3 end subscript horizontal ellipsis horizontal ellipsis equals negative 1
Statement-II : x subscript n end subscript equals c o s invisible function application open parentheses pi divided by 4 to the power of n end exponent close parentheses plus i s i n invisible function application open parentheses pi divided by 4 to the power of n end exponent close parentheses then x subscript 1 end subscript times x subscript 2 end subscript times x subscript 3 end subscript horizontal ellipsis horizontal ellipsis infinity equals negative 1

  1. Only I is true    
  2. Only II is true    
  3. Both I and II are true    
  4. Neither I nor II are true    

The correct answer is: Only I is true

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