Maths-
General
Easy
Question
The are of the triangle inscribed in the parabola y2 = 4x, the ordinates of whose vertices are 1, 2 and 4 is
- 7/2 sq. unit
- 5/2 sq. unit
- 3/2 sq. unit
- 3/4 sq. unit
The correct answer is: 3/4 sq. unit
To find the area of the triangle inscribed inside parabola.
Given, 1,2,4 are the coordinates and parabola .
for y=1, x = ; y=2, x = 1; y=4, x=4.
so, the vertices are (,1) , (1,2), (4,4).
area of the triangle =
= 1/2 (-1/2+3-4)
=3/4 sq. unit
Therefore, the area of the triangle is 3/4 sq. unit.
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