Maths-
General
Easy
Question
The area bounded by the parabola
and the line 2x-3y+4=0, in square units, is

- 1
- 1/2
- 2/5
- 1/3
The correct answer is: 1/3
Related Questions to study
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The area (in square units)bounded by the curves y=
a x is, and lying in the first quadrant is

The area (in square units)bounded by the curves y=
a x is, and lying in the first quadrant is

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and above x-axis is:

The area under the curve y=
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The area of the region (in sq. units), in the first quadrant, bounded by the parabola y=
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The area bounded by the curve y=ln (x) and the lines y=0, y=ln(3) and x=0 is equal to:

The area bounded by the curve y=ln (x) and the lines y=0, y=ln(3) and x=0 is equal to:

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Let A=
The area (in square units) of the region A is:

Let A=
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The area (in sq units) of the region bounded by the curves
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The area between the parabolas
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The area of the region between the curve
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The area of the region between the curve
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The area of the region bounded by y=|x-1| and y=1 in sq. units is

The area of the region bounded by y=|x-1| and y=1 in sq. units is

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The area of the elliptic quadratic with the semi major axis and semi minor axis as 6 and 4 respectively

The area of the elliptic quadratic with the semi major axis and semi minor axis as 6 and 4 respectively

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The area of circle circumscribing ΔABC is
The area of circle circumscribing ΔABC is
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Statement-I : The statement that circumradius and inradius of a triangle are 12 and 8 respectively can not be correct. Statement-II : Circumradius 2 (inradius)
Statement-I : The statement that circumradius and inradius of a triangle are 12 and 8 respectively can not be correct. Statement-II : Circumradius 2 (inradius)
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The complete solution set of the equation
is
The complete solution set of the equation
is
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The solution(s) of the equation cos2x sin6x = cos3x sin5x in the interval [0,
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The solution(s) of the equation cos2x sin6x = cos3x sin5x in the interval [0,
] is/are –
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The equation
has
The equation
has
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