Maths-
SAT
Easy

Question

The graphs in the xy-plane of the following quadratic equations each have x-intercepts of -2 and 4. The graph of which equation has its vertex  farthest from the x-axis

  1. y = - 7(x + 2) (x - 4)
  2. y equals 1 over 10 left parenthesis x plus 2 right parenthesis left parenthesis x minus 4 right parenthesis
  3. y equals negative 1 half left parenthesis x plus 2 right parenthesis left parenthesis x minus 4 right parenthesis
  4. y = 5(x + 2)(x - 4)

The correct answer is: y = - 7(x + 2) (x - 4)


    Given x- intercept = -2, 4
    (x + 2)  (x - 4)
    Let y = p(x+2)(x - 4)
    y = p(x2 – 2x - 8)
    y’ = p(2x - 1) = 0
    x = 1 half
    vertex is at x = 1 half
    so, highest absolute value of p, higher will be the absolute value of y at vertex. From x-axis
    From options
    vertical line minus 7 vertical line greater than vertical line 5 vertical line greater than open vertical bar fraction numerator negative 1 over denominator 2 end fraction close vertical bar greater than open vertical bar 1 over 10 close vertical bar
    y = -7(x+ 2)(x - 4)

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