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Maths-

General

Easy

Question

The line $2 x plus 3 y equals 1$ cuts the circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4$ in $P$ and Q Then the equation of the smaller circle passing through $P$ and $Q$

$13 (x^{2} + y^{2}) - 4 x - 6 y + 50 = 0$
$13 (x^{2} + y^{2}) - 6 y - 50 = 0$
$13 (x^{2} + y^{2}) - 4 x - 6 y - 50 = 0$
$13 (x^{2} + y^{2}) - 4 x - 50 = 0$

The correct answer is: $13 left parenthesis x to the power of 2 end exponent plus y to the power of 2 end exponent right parenthesis minus 4 x minus 6 y minus 50 equals 0$

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