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Easy

Question

The number of numbers of 9 different non-zero digits such that all the digits in the first four places are less than the digit in the middle and all the digits in the last four places are greater than the digit in the middle is

  1. 2 left parenthesis 4 factorial right parenthesis    
  2. left parenthesis 4 factorial right parenthesis to the power of 2 end exponent    
  3. 8 factorial    
  4. 2 cross times open parentheses 4 right parenthesis squared close    

The correct answer is: left parenthesis 4 factorial right parenthesis to the power of 2 end exponent


    Fix 5 at middle place, 1, 2, 3, 4 on left side and 6, 7, 8, 9 on right side can be arranged in left parenthesis 4 factorial right parenthesis to the power of 2 end exponent ways

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