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Question

The solution of the differential equation x d y minus y d x equals left parenthesis square root of x to the power of 2 end exponent plus y to the power of 2 end exponent right parenthesis end root d x is

  1. y minus square root of x to the power of 2 end exponent plus y to the power of 2 end exponent end root equals c x to the power of 2 end exponent    
  2. y plus square root of x to the power of 2 end exponent plus y to the power of 2 end exponent end root equals c x to the power of 2 end exponent    
  3. y plus square root of x to the power of 2 end exponent plus y to the power of 2 end exponent end root plus c x to the power of 2 end exponent equals 0    
  4. None of these    

The correct answer is: y plus square root of x to the power of 2 end exponent plus y to the power of 2 end exponent end root equals c x to the power of 2 end exponent


    It is a homogenous equation, solve it by putting y equals v xand fraction numerator d y over denominator d x end fraction equals v plus x fraction numerator d v over denominator d x end fraction.

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