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0 with hat on top subscript 1 superscript 1 fraction numerator sin invisible function application x minus x squared over denominator 3 minus vertical line x vertical line end fraction d x equals

  1. 0
  2. 2 straight Q with hat on top to the power of 1 fraction numerator sin invisible function application straight x over denominator 3 minus vertical line straight x vertical line end fraction dx    
  3. straight Q with hat on top to the power of 1 fraction numerator negative 2 straight x squared over denominator 3 minus vertical line straight x vertical line end fraction dx    
  4. 2 straight Q with hat on top to the power of 1 fraction numerator sin invisible function application straight x minus straight x squared over denominator 3 minus vertical line straight x vertical line end fraction dx    

The correct answer is: straight Q with hat on top to the power of 1 fraction numerator negative 2 straight x squared over denominator 3 minus vertical line straight x vertical line end fraction dx

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