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Physics-

General

Easy

Question

1 Pico is

10¹⁰
10^–10
10^–12
10¹²

The correct answer is: 10^–12

Related Questions to study

1 nano is

1 nano is

physics-General

Interference proves:

Interference proves:

physics-General

In the figure, $stack D E with bar on top divided by divided by stack B C with bar on top$ and area ( $triangle$ A D E) = area ( $triangle$ B C E D) The value of $fraction numerator B D over denominator A B end fraction equals$

In the figure, $stack D E with bar on top divided by divided by stack B C with bar on top$ and area ( $triangle$ A D E) = area ( $triangle$ B C E D) The value of $fraction numerator B D over denominator A B end fraction equals$

parallel

In $triangle$ ABC , D and E are the points on $stack A B with bar on top text and end text stack A C with bar on top$ respectively such that $stack D E with bar on top divided by divided by stack B C with bar on top$ If AB = 3 AD and the area of $triangle$ ABC is 72 cm², then the area of Quadrilateral DBCE is cm².

In $triangle$ ABC , D and E are the points on $stack A B with bar on top text and end text stack A C with bar on top$ respectively such that $stack D E with bar on top divided by divided by stack B C with bar on top$ If AB = 3 AD and the area of $triangle$ ABC is 72 cm², then the area of Quadrilateral DBCE is cm².

In two similar triangles ABC and DEF, AB = 5cm, DE = 9cm If the area of $triangle$ DEF is 405 cm² then area of $triangle$ ABC = cm².

Therefore, area of $triangle$ ABC is 125 $c m squared$ .

In two similar triangles ABC and DEF, AB = 5cm, DE = 9cm If the area of $triangle$ DEF is 405 cm² then area of $triangle$ ABC = cm².

Therefore, area of $triangle$ ABC is 125 $c m squared$ .

In the figure, $angle A equals angle C E D comma$ AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?

In the figure, $angle A equals angle C E D comma$ AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?

parallel

In the figure, $stack A B with bar on top divided by divided by stack Q R with bar on top$ If AB = 3 cm, PB = 2 cm and PR = 6 cm then QR = ? cm.

In the figure, $stack A B with bar on top divided by divided by stack Q R with bar on top$ If AB = 3 cm, PB = 2 cm and PR = 6 cm then QR = ? cm.

In the figure, $stack A B with rightwards arrow on top H stack C D with bar on top text and end text stack A C with bar on top intersection stack B D with bar on top equals 0 blank$ If OA = 3x – 1, OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC = ? units.

In the figure, $stack A B with rightwards arrow on top H stack C D with bar on top text and end text stack A C with bar on top intersection stack B D with bar on top equals 0 blank$ If OA = 3x – 1, OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC = ? units.

Two line segments $stack A B with bar on top$ and $stack C D with bar on top$ intersect at E such that $triangle A C E tilde operator triangle B D E equals$ If AE=4cm,BE=3cm,CE=6cm and DE=xcm then x = ?

Two line segments $stack A B with bar on top$ and $stack C D with bar on top$ intersect at E such that $triangle A C E tilde operator triangle B D E equals$ If AE=4cm,BE=3cm,CE=6cm and DE=xcm then x = ?

parallel

From the adjacent figure ,the values of x and y are

From the adjacent figure ,the values of x and y are

In the given figure, ABC is an Isosceles Triangle in which AB = AC, then

In the given figure, ABC is an Isosceles Triangle in which AB = AC, then

In $triangle A B C comma 2 angle A equals 3 angle B equals 6 angle C$ then $angle$ A =?

In $triangle A B C comma 2 angle A equals 3 angle B equals 6 angle C$ then $angle$ A =?

parallel

In the figure, AB = BC = CD = DE = EF and AF = AE Then $angle$ A = ?

In the figure, AB = BC = CD = DE = EF and AF = AE Then $angle$ A = ?

In the figure, AB = AC, $angle A equals 48 to the power of 0 end exponent$ and $angle A C D equals 18 to the power of ring operator end exponent$ Then

In the figure, AB = AC, $angle A equals 48 to the power of 0 end exponent$ and $angle A C D equals 18 to the power of ring operator end exponent$ Then

In the figure, $´ x to the power of 0 end exponent text ´ end text$ and $text ´ end text y to the power of text 0 end text text ´ end text end exponent$ are two exterior angle measures of $triangle$ ABC Then $x to the power of 0 end exponent plus y to the power of 0 end exponent$ is

In the figure, $´ x to the power of 0 end exponent text ´ end text$ and $text ´ end text y to the power of text 0 end text text ´ end text end exponent$ are two exterior angle measures of $triangle$ ABC Then $x to the power of 0 end exponent plus y to the power of 0 end exponent$ is

parallel

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