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A boy throws a ball upwards with velocity v subscript 0 end subscript equals 20 m divided by s The wind imparts a horizontal acceleration of 4 text end text m divided by s to the power of 2 end exponent to the left. The angle theta at which the ball must be thrown so that the ball returns to the boy's hand is open parentheses g equals 10 text end text m divided by s to the power of 2 end exponent close parentheses

  1. t a n to the power of negative 1 end exponent invisible function application left parenthesis 12 right parenthesis    
  2. t a n to the power of negative 1 end exponent invisible function application left parenthesis 0.2 right parenthesis    
  3. t a n to the power of negative 1 end exponent invisible function application left parenthesis 2 right parenthesis    
  4. t a n to the power of negative 1 end exponent invisible function application left parenthesis 0.4 right parenthesis    

The correct answer is: t a n to the power of negative 1 end exponent invisible function application left parenthesis 0.4 right parenthesis

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