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A child with mass m is standing at the edge of a mery-go-round having moment as shown in the figure. The omega of inertia I, radius R and initial angular velocity child jumps off the edge of the merry-go-round with tangential velocity v with respect to the ground. The new angular velocity of the merry-go-round is :

  1. square root of fraction numerator I omega to the power of 2 end exponent minus m v to the power of 2 end exponent over denominator I end fraction end root    
  2. square root of fraction numerator open parentheses I plus m R to the power of 2 end exponent close parentheses omega to the power of 2 end exponent minus m v to the power of 2 end exponent over denominator I end fraction end root    
  3. fraction numerator I omega minus m v R over denominator I end fraction    
  4. fraction numerator open parentheses I plus m R to the power of 2 end exponent close parentheses omega minus m v R over denominator I end fraction    

The correct answer is: fraction numerator open parentheses I plus m R to the power of 2 end exponent close parentheses omega minus m v R over denominator I end fraction

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