Physics-
General
Easy

Question

A conducting rod of length l and mass m is moving down a smooth inclined plane of inclination qwith constant velocity v in fig. A current I is flowing in the conductor in a direction perpendicular to paper inwards. A vertically upward magnetic field B exists in space. Then magnitude of magnetic field B is

  1. fraction numerator m g over denominator i l end fraction s i n invisible function application theta    
  2. fraction numerator m g over denominator i l end fraction t a n invisible function application theta    
  3. fraction numerator m g c o s invisible function application theta over denominator i l end fraction    
  4. fraction numerator m g over denominator i l s i n invisible function application theta end fraction    

The correct answer is: fraction numerator m g over denominator i l end fraction t a n invisible function application theta


    text For constant velocity  end text a equals 0 equals gsin invisible function application theta minus fraction numerator i l Bcos invisible function application theta over denominator m end fraction
    rightwards double arrow B equals fraction numerator m g t a n invisible function application theta over denominator i l end fraction

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