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Physics-

General

Easy

Question

A cone of radius R and height H, is hanging inside a liquid of density $rho$ by means of a string as shown in the figure. The force, due to the liquid acting on the slant surface of the cone is

$ρ π {g H R}^{2}$
$π ρ {H R}^{2}$
$\frac{4}{3} π ρ g {H R}^{2}$
$\frac{2}{3} π ρ {g H R}^{2}$

The correct answer is: $fraction numerator 2 over denominator 3 end fraction pi rho g H R to the power of 2 end exponent$

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The vertical limbs of a U shaped tube are filled with a liquid of density $rho$ upto a height h on each side. The horizontal portion of the U tube having length 2h contains a liquid of density 2 $rho$ . The U tube is moved horizontally with an accelerator g/2 parallel to the horizontal arm. The difference in heights in liquid levels in the two vertical limbs, at steady state will be

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