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General
Easy

Question

A hollow conducting sphere of inner radius R and outer radius 2R has resistivity distance 'r' from the centre of the sphere: rho equals k r to the power of 2 end exponent divided by R. The inner and outer surfaces are painted with a V is applied between the two surfaces. Then, as perfectly conducting 'paint' and a potential difference 'r' increases from R to 2R, the electric field inside the sphere

  1. increases    
  2. decreases    
  3. remains constant    
  4. passes through a maxima    

The correct answer is: remains constant

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