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General
Easy

Question

A large cylindrical tank of cross-sectional area 1m to the power of 2 end exponent is filled with water. It has a small hole at a height of 1m from the bottom. A movable piston of mass 5 kg is fitted on the top of the tank such that it can slide in the tank freely. A load of 45 kg is applied on the top of water by piston, as shown in figure. The value of v when piston is 7m above the bottom is (g = 10 m divided by s to the power of 2 end exponent)

  1. square root of 120 m divided by s    
  2. 10 m/s    
  3. 1 m/s    
  4. 11 m/s    

The correct answer is: 11 m/s


    fraction numerator 1 over denominator 2 end fraction rho v to the power of 2 end exponent equals rho g h plus fraction numerator M g over denominator A end fraction rightwards double arrow v equals square root of 2 g h plus fraction numerator 2 M g over denominator rho A end fraction end root equals square root of 2 cross times 10 cross times 6 plus fraction numerator 2 cross times 50 cross times 10 over denominator 10 to the power of 3 end exponent cross times 1 end fraction end root equals square root of 120 plus 1 end root equals square root of 121 equals 11 m divided by s

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