Physics-
General
Easy

Question

A magnetic field (B), uniform between two magnets can be determined measuring the induced voltage in the loop as it is pulled through the gap at uniform speed 20 m/sec. Size of magnet and coil is 2 c m cross times 1 c m cross times 2 c m and 4 c m cross times 6 c m as shown in figure. The correct variation of induced emf with time is : (Assume at t = 0, the coil enters in the magnetic field)

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The correct answer is:


    E equals fraction numerator d ϕ over denominator d t end fraction equals fraction numerator B d open parentheses b l close parentheses over denominator d t end fraction
    table row cell equals B b v equals B cross times 2 cross times 10 to the power of negative 2 end exponent cross times 20 equals 0.40 B end cell row cell capital delta t equals fraction numerator 1 cross times 10 to the power of negative 2 end exponent over denominator 20 end fraction equals 5 cross times 10 to the power of negative 4 end exponent s e c equals 500 mu s e c end cell row cell t equals fraction numerator 6 cross times 10 to the power of negative 2 end exponent over denominator 20 end fraction equals 3 cross times 10 to the power of negative 3 end exponent s e c equals 3000 mu s e c end cell end table

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