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A monochromatic light source of wavelength is placed at S. Three slits S1 , S2 and S3 are equidistant from the source S and the point P on the screen. S1P – S2P = /6 and S1P – S3P = 2/3. If I be the intensity at P when only one slit is open, the intensity at P when all the three slits are open is
- 3 I
- 5 I
- 8 I
- zero
The correct answer is: 3 I
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