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Physics-

General

Easy

Question

A particle is moving on a circular path of radius $r$ with uniform velocity $v$ . The change in velocity when the particle moves from $P blank$ to $blank Q blank$ is $blank left parenthesis angle P O Q equals 40 degree right parenthesis$

$2 v \cos 40 °$
$2 v \sin 40 °$
$2 v \sin 20 °$
$2 v \cos 20 °$

The correct answer is: $2 v sin invisible function application 20 degree$

Change in velocity $equals 2 v sin invisible function application open parentheses theta divided by 2 close parentheses equals 2 v sin invisible function application 20 degree$

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