Physics-
General
Easy

Question

A particle of mass m is projected at an angle of 60° with a velocity of 20 m/s relative to the ground from a plank of same mass m which is placed on smooth surface Initially plank was at rest The minimum length of the plank for which the ball will fall on the plank itself is

  1. 40 square root of 3 m    
  2. 20 square root of 3 m    
  3. 10 square root of 3 m    
  4. 60 square root of 3 m    

The correct answer is: 20 square root of 3 m


    time of flight =fraction numerator 2 open parentheses 20 s i n invisible function application 60 to the power of ring operator end exponent close parentheses over denominator g end fraction
    Displacement of particle in this interval =fraction numerator u to the power of 2 end exponent s i n invisible function application 2 theta over denominator g end fraction equals 20 square root of 3 m

    displacement of plank in this interval = 20 square root of 3 m
    Total = 40 square root of 3 m

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