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General
Easy
Question
A particle starts from the point (0m, 8m) and moves with uniform velocity of 
. After 5 seconds, the angular velocity of the particle about the origin will be :
The correct answer is:
Related Questions to study
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A uniform rod is fixed to a rotating turntable so that its lower end is on the axis of the turntable and it makes an angle of 20° to the vertical. (The rod is thus rotating with uniform angular velocity about a vertical axis passing through one end.) If the turntable is rotating clockwise as seen from above. Is there a torque acting on it, and if so in what direction?
A uniform rod is fixed to a rotating turntable so that its lower end is on the axis of the turntable and it makes an angle of 20° to the vertical. (The rod is thus rotating with uniform angular velocity about a vertical axis passing through one end.) If the turntable is rotating clockwise as seen from above. Is there a torque acting on it, and if so in what direction?
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A uniform rod is fixed to a rotating turntable so that its lower end is on the axis of the turntable and it makes an angle of 20° to the vertical. (The rod is thus rotating with uniform angular velocity about a vertical axis passing through one end.) If the turntable is rotating clockwise as seen from above. What is the direction of the rod's angular momentum vector (calculated about its lower end)?
A uniform rod is fixed to a rotating turntable so that its lower end is on the axis of the turntable and it makes an angle of 20° to the vertical. (The rod is thus rotating with uniform angular velocity about a vertical axis passing through one end.) If the turntable is rotating clockwise as seen from above. What is the direction of the rod's angular momentum vector (calculated about its lower end)?
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A child with mass m is standing at the edge of a disc with moment of inertia I, radius R, and initial angular velocity w. See figure given below. The child jumps off the edge of the disc with tangential velocity v with respect to the ground. The new angular velocity of the disc is
A child with mass m is standing at the edge of a disc with moment of inertia I, radius R, and initial angular velocity w. See figure given below. The child jumps off the edge of the disc with tangential velocity v with respect to the ground. The new angular velocity of the disc is
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A particle of mass m is rotating in a plane is a circular path of radius r, its angular momentum is L. The centripetal force acting on the particle is :
A particle of mass m is rotating in a plane is a circular path of radius r, its angular momentum is L. The centripetal force acting on the particle is :
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A particle is moving in a circular orbit of radius r1 with an angular velocity 
. It jumps to another circular orbit of radius r2 and attains an angular velocity 
. If r2 = 0.5 r1 and assuming that no external torque is applied to the system, then the angular velocity , is given by :
A particle is moving in a circular orbit of radius r1 with an angular velocity . It jumps to another circular orbit of radius r2 and attains an angular velocity . If r2 = 0.5 r1 and assuming that no external torque is applied to the system, then the angular velocity , is given by :
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A small bead of mass m moving with velocity v gets threaded on a stationary semicircular ring of mass m and radius R kept on a horizontal table. The ring can freely rotate about its centre. The bead comes to rest relative to the ring. What will be the final angular velocity of the system?
A small bead of mass m moving with velocity v gets threaded on a stationary semicircular ring of mass m and radius R kept on a horizontal table. The ring can freely rotate about its centre. The bead comes to rest relative to the ring. What will be the final angular velocity of the system?
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A block of mass m is attached to a pulley disc of equal mass m, radius r by means of a slack string as shown. The pulley is hinged about its centre on a horizontal table and the block is projected with an initial velocity of 5 m/s. Its velocity when the string becomes taut will be
A block of mass m is attached to a pulley disc of equal mass m, radius r by means of a slack string as shown. The pulley is hinged about its centre on a horizontal table and the block is projected with an initial velocity of 5 m/s. Its velocity when the string becomes taut will be
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A rod hinged at one end is released from the horizontal position as shown in the figure. When it becomes vertical its lower half separates without exerting any reaction at the breaking point. Then the maximum angle 
made by the hinged upper half with the vertical is
A rod hinged at one end is released from the horizontal position as shown in the figure. When it becomes vertical its lower half separates without exerting any reaction at the breaking point. Then the maximum angle made by the hinged upper half with the vertical is
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A pulley is hinged at the centre and a massless thread is wrapped around it. The thread is pulled with a constant force F starting from rest. As the time increases
A pulley is hinged at the centre and a massless thread is wrapped around it. The thread is pulled with a constant force F starting from rest. As the time increases
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A uniform rod of mass m and length l hinged at its end is released from rest when it is in the horizontal position. The normal reaction at the hinge when the rod becomes vertical is :
A uniform rod of mass m and length l hinged at its end is released from rest when it is in the horizontal position. The normal reaction at the hinge when the rod becomes vertical is :
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An object is placed in front of a symmetrical convex lens with refractive index 1.5 and radius of curvature 40 cm. The surface of the lens further away from the object is silvered. Under auto-collimation condition, the object distance is
An object is placed in front of a symmetrical convex lens with refractive index 1.5 and radius of curvature 40 cm. The surface of the lens further away from the object is silvered. Under auto-collimation condition, the object distance is
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A thin symmetric double - convex lens of power P is cut into three parts A, B and C as shown. The power of
A thin symmetric double - convex lens of power P is cut into three parts A, B and C as shown. The power of
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A point object O moves from the principal axis of a converging lens in a direction OP. I is the image of O, will move initially in the direction
A point object O moves from the principal axis of a converging lens in a direction OP. I is the image of O, will move initially in the direction
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The figure, shows a transparent sphere of radius R and refractive index m. An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface. In previous problem, if the refractive index of the sphere is varied, then the position x of the object and its image from the respective poles will also vary. Identify the correct statement
The figure, shows a transparent sphere of radius R and refractive index m. An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface. In previous problem, if the refractive index of the sphere is varied, then the position x of the object and its image from the respective poles will also vary. Identify the correct statement
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physics-
The figure, shows a transparent sphere of radius R and refractive index 
. An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface. If an object is placed at a distance R from the pole of first surface, then the real image is formed at a distance R from the pole of the second surface. The refractive index m of the sphere is given by
The figure, shows a transparent sphere of radius R and refractive index . An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface. If an object is placed at a distance R from the pole of first surface, then the real image is formed at a distance R from the pole of the second surface. The refractive index m of the sphere is given by
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