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Physics-

General

Easy

Question

A physical quantity $P blank$ is given by $P equals fraction numerator A to the power of 3 end exponent B to the power of fraction numerator 1 over denominator blank 2 end fraction end exponent over denominator C to the power of negative 4 end exponent D to the power of fraction numerator 3 over denominator 2 end fraction end exponent end fraction.$ The quantity which brings in the maximum percentage error in $P$ is

A
B
C
D

The correct answer is: C

Quantity $C$ has maximum power. So it brings maximum error in $P$

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Students I, II and III perform an experiment for measuring the acceleration due to gravity $left parenthesis g right parenthesis$ using a simple pendulum. They use different lengths of the pendulum and/or record time for different number of oscillations. The observations are shown in the table
Least count for length $equals 0.1 blank c m$
Least count for time $equals 0.1 blank s$

If $E subscript I end subscript comma blank E subscript I I end subscript$ and $E subscript I I I end subscript$ are the percentage errors in $g comma blank i. e. comma blank open parentheses fraction numerator increment g over denominator g end fraction cross times 100 close parentheses$ for students I, II and III, respectively

Students I, II and III perform an experiment for measuring the acceleration due to gravity $left parenthesis g right parenthesis$ using a simple pendulum. They use different lengths of the pendulum and/or record time for different number of oscillations. The observations are shown in the table
Least count for length $equals 0.1 blank c m$
Least count for time $equals 0.1 blank s$

If $E subscript I end subscript comma blank E subscript I I end subscript$ and $E subscript I I I end subscript$ are the percentage errors in $g comma blank i. e. comma blank open parentheses fraction numerator increment g over denominator g end fraction cross times 100 close parentheses$ for students I, II and III, respectively

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The unit of e.m.f is

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The correct relationship between free energy change in a reaction and the corresponding equilibrium constant K_C is

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant K_C is

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The relationship between free energy and electrode potential is

The relationship between free energy and electrode potential is

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For a spontaneous reaction the $increment$ G , equilibrium constant (K) and $E subscript text cell end text end subscript superscript 0 end superscript$ will be respectively

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For a cell reaction, $C u to the power of 2 plus end exponent open parentheses C subscript 1 end subscript comma a q close parentheses plus Z n left parenthesis s right parenthesis rightwards arrow Z n to the power of 2 plus end exponent open parentheses C subscript 2 end subscript comma a q close parentheses plus C u left parenthesis s right parenthesis$ of an electro chemical cell, the change in standard free energy, $increment$ G⁰ at a given temperature is

For a cell reaction, $C u to the power of 2 plus end exponent open parentheses C subscript 1 end subscript comma a q close parentheses plus Z n left parenthesis s right parenthesis rightwards arrow Z n to the power of 2 plus end exponent open parentheses C subscript 2 end subscript comma a q close parentheses plus C u left parenthesis s right parenthesis$ of an electro chemical cell, the change in standard free energy, $increment$ G⁰ at a given temperature is

chemistry-General

For the electrochemical cell, $M open vertical bar M to the power of plus end exponent close vertical bar open vertical bar X to the power of minus end exponent close vertical bar X comma E subscript M to the power of plus end exponent divided by M end subscript superscript ring operator end superscript equals negative 0.44 V$ and $E subscript X divided by X to the power of minus end exponent end subscript superscript ring operator end superscript$ From this data, one can deduce that :

For the electrochemical cell, $M open vertical bar M to the power of plus end exponent close vertical bar open vertical bar X to the power of minus end exponent close vertical bar X comma E subscript M to the power of plus end exponent divided by M end subscript superscript ring operator end superscript equals negative 0.44 V$ and $E subscript X divided by X to the power of minus end exponent end subscript superscript ring operator end superscript$ From this data, one can deduce that :

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The circular scale of a screw gauge has 50 divisions and pitch of 0.5 mm. Find the diameter of sphere. Main scale reading is 2.

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